9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
1) 12 ounces of water to one packet of flavoring
2) 5 = 60, 7 = 84, 10 = 120, 12 = 144
4) 23 x 12 = 276 ounces of water
Answer: 
Step-by-step explanation:
Given
The slant height of the square pyramid is 
The length of the side of the base is 
for the square pyramid, height is given by
![\Rightarrow h=\sqrt{l^2-r^2}\quad \quad [\text{where r=}\frac{a}{2}]\\\Rightarrow h=\sqrt{25^2-7^2}\\\Rightarrow h=\sqrt{625-49}\\\Rightarrow h=\sqrt{576}\\\Rightarrow h=24\ ft](https://tex.z-dn.net/?f=%5CRightarrow%20h%3D%5Csqrt%7Bl%5E2-r%5E2%7D%5Cquad%20%5Cquad%20%5B%5Ctext%7Bwhere%20r%3D%7D%5Cfrac%7Ba%7D%7B2%7D%5D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B25%5E2-7%5E2%7D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B625-49%7D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B576%7D%5C%5C%5CRightarrow%20h%3D24%5C%20ft)
Thus, the height of the prism is
Your equation is a little messed up comment me the equation you need help with
This is an adjacent angle. Both the angles have an common side and a common vertex. Hope this helped :)