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Naily [24]
3 years ago
14

Which of these tables represents a linear function? A 2-column table with 4 rows. Column 1 is labeled x with entries 3, 4, 5, 6.

Column 2 is labeled y with entries 3, 4, 6, 7. A 2-column table with 4 rows. Column 1 is labeled x with entries 3, 4, 5, 6. Column 2 is labeled y with entries 6, 5, 4, 3. A 2-column table with 4 rows. Column 1 is labeled x with entries 3, 4, 5, 6. Column 2 is labeled y with entries 7, 6, 5, 3. A 2-column table with 4 rows. Column 1 is labeled x with entries 3, 4, 5, 6. Column 2 is labeled y with entries 2, 4, 5, 6.
Mathematics
2 answers:
yulyashka [42]3 years ago
7 0

Answer:

B

Step-by-step explanation:

    The other tables don't increase or decrease by only one number.  I'm pretty sure it's B. If it isn't, my apologies.

Sedbober [7]3 years ago
5 0

Answer:

the table :

(-3,8.5) .....x1 = -3 and y1 = 8.5

(-1,5.5) ....x2 = -1 and y2 = 5.5

slope = (y2 - y1) / (x2 - x1) = (5.5 - 8.5) / (-1 - (-3) = - 3 / (-1 + 3) = -3/2

coordinate plane :

(-3,0), (2,0)

notice how u have the same y values of 0....this means u have a horizontal line where no matter what x is, y will always be 0. A horizontal line has a slope of 0. And ur y intercept is (0,0)

the linear function that is in the table contains a negative slope and also has a steeper slope then the one on the coordinate plane <===

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Diego’s dog weighs more than 10 kilograms and less than 15 kilograms. Select the set of inequalities that must be true if w is t
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Answer:

Step-by-step explanation:

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7 0
2 years ago
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)equals72 com
solmaris [256]

Answer:

Part (A)

  • 1. Maximum revenue: $450,000

Part (B)

  • 2. Maximum protit: $192,500
  • 3. Production level: 2,300 television sets
  • 4. Price: $185 per television set

Part (C)

  • 5. Number of sets: 2,260 television sets.
  • 6. Maximum profit: $183,800
  • 7. Price: $187 per television set.

Explanation:

<u>0. Write the monthly cost and​ price-demand equations correctly:</u>

Cost:

      C(x)=72,000+70x

Price-demand:

     

      p(x)=300-\dfrac{x}{20}

Domain:

        0\leq x\leq 6000

<em>1. Part (A) Find the maximum revenue</em>

Revenue = price × quantity

Revenue = R(x)

           R(x)=\bigg(300-\dfrac{x}{20}\bigg)\cdot x

Simplify

      R(x)=300x-\dfrac{x^2}{20}

A local maximum (or minimum) is reached when the first derivative, R'(x), equals 0.

         R'(x)=300-\dfrac{x}{10}

Solve for R'(x)=0

      300-\dfrac{x}{10}=0

       3000-x=0\\\\x=3000

Is this a maximum or a minimum? Since the coefficient of the quadratic term of R(x) is negative, it is a parabola that opens downward, meaning that its vertex is a maximum.

Hence, the maximum revenue is obtained when the production level is 3,000 units.

And it is calculated by subsituting x = 3,000 in the equation for R(x):

  • R(3,000) = 300(3,000) - (3000)² / 20 = $450,000

Hence, the maximum revenue is $450,000

<em>2. Part ​(B) Find the maximum​ profit, the production level that will realize the maximum​ profit, and the price the company should charge for each television set. </em>

i) Profit(x) = Revenue(x) - Cost(x)

  • Profit (x) = R(x) - C(x)

       Profit(x)=300x-\dfrac{x^2}{20}-\big(72,000+70x\big)

       Profit(x)=230x-\dfrac{x^2}{20}-72,000\\\\\\Profit(x)=-\dfrac{x^2}{20}+230x-72,000

ii) Find the first derivative and equal to 0 (it will be a maximum because the quadratic function is a parabola that opens downward)

  • Profit' (x) = -x/10 + 230
  • -x/10 + 230 = 0
  • -x + 2,300 = 0
  • x = 2,300

Thus, the production level that will realize the maximum profit is 2,300 units.

iii) Find the maximum profit.

You must substitute x = 2,300 into the equation for the profit:

  • Profit(2,300) = - (2,300)²/20 + 230(2,300) - 72,000 = 192,500

Hence, the maximum profit is $192,500

iv) Find the price the company should charge for each television set:

Use the price-demand equation:

  • p(x) = 300 - x/20
  • p(2,300) = 300 - 2,300 / 20
  • p(2,300) = 185

Therefore, the company should charge a price os $185 for every television set.

<em>3. ​Part (C) If the government decides to tax the company ​$4 for each set it​ produces, how many sets should the company manufacture each month to maximize its​ profit? What is the maximum​ profit? What should the company charge for each​ set?</em>

i) Now you must subtract the $4  tax for each television set, this is 4x from the profit equation.

The new profit equation will be:

  • Profit(x) = -x² / 20 + 230x - 4x - 72,000

  • Profit(x) = -x² / 20 + 226x - 72,000

ii) Find the first derivative and make it equal to 0:

  • Profit'(x) = -x/10 + 226 = 0
  • -x/10 + 226 = 0
  • -x + 2,260 = 0
  • x = 2,260

Then, the new maximum profit is reached when the production level is 2,260 units.

iii) Find the maximum profit by substituting x = 2,260 into the profit equation:

  • Profit (2,260) = -(2,260)² / 20 + 226(2,260) - 72,000
  • Profit (2,260) = 183,800

Hence, the maximum profit, if the government decides to tax the company $4 for each set it produces would be $183,800

iv) Find the price the company should charge for each set.

Substitute the number of units, 2,260, into the equation for the price:

  • p(2,260) = 300 - 2,260/20
  • p(2,260) = 187.

That is, the company should charge $187 per television set.

7 0
2 years ago
A group of rectangular prisms is shown.
scoray [572]

Answer:

D, E and F

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you need some addition for surface area and for more complicated bodies that when the volume can't be calculated in one step

8 0
2 years ago
ANHL player's labor negotiating committee is to be selected from 8 player representatives from the Eastern Conference and 7 play
cestrela7 [59]

Answer:

21 / 143

Step-by-step explanation:

Given that:

Number of Eastern conference reps = 8

Number of western conference rep = 7

Probability of selecting 3 from Eastern reps and 2 from western reps

Probability = required outcome / Total possible outcomes

Total possible outcomes:

selection to be made = 3+ 2 = 5

Total Number of players = 8 +7 = 15

Total possible outcomes

Using combination formula :

nCr = n! / (n-r)!r!

15C5 = 15! / 10!5! = (15 * 14 * 13 * 12 * 11) / (5*4'3*2*1) = 360360 / 120 = 3003

Total possible outcomes = 3003

Required outcome :

8C3 * 7C2

8C3 = 56 ; 7C2 = 21

8C3 * 7C2 = 56 * 21 = 1176

required outcome / Total possible outcomes

= 1176 / 3003

= 21 / 143

6 0
3 years ago
Find 2.2℅ of 18 2/11?
UNO [17]
The answer to ur question is 0.396
2.2% * 18 = 0.396
7 0
3 years ago
Read 2 more answers
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