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3 years ago

6.

Mathematics

1 answer:

Readme [11.4K]3 years ago

6 0

<span>Any ordered pair in a system that makes all the equations true

</span>

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I need help. Say two squirrels are mating in a tree and that tree is 56 feet tall. How many babies would they have if the sun wa

Natasha_Volkova [10]

OK. Math is a SERIOUS subject...... ...........This is a SERIOUS website were students come to LEARN and SHARE ideas and HELP each other with SERIOUS scholarly work.......... Do not slander this website with ur "Joke" questions. Becuse it leads NOWHERE....... ..... DO NOT BRING UR SLANDEROUS STUPID NONSENSE QUESTIONS INTO THIS WEBSITE......I WILL report you to the mods. OK? AGH people like U is why i hate this gernation................... -_-

4 0

3 years ago

In the collection of beads, StartFraction 4 Over 20 EndFraction are blue. Which model shows the percent of beads that are blue?

jolli1 [7]

Option B model shows the percent of beads that are blue.

Solution:

Fraction of beads blue = $\frac{4}{20}$

To convert it into percent multiply the fraction by 100.

$$\text {Percent of} \ \frac{4}{20}=\frac{4}{20}\times 100\%$

$$=\frac{4\times 100}{20} \%$

Cancel the common factors, we get

= 20%

$$=\frac{20}{100}$

This means total number of boxes 100 and shaded in blue color 20.

Therefore option 2 represents $\frac{20}{100}$ .

Hence option B model shows the percent of beads that are blue.

8 0

3 years ago

Easy math, but not sure what I did wrong.

Ierofanga [76]

Answer:

Step-by-step explanation:

In his 5th year, he took 3 times as many exams as the first year. So the number of exams taken in the 5th year must be a multiple of 3.

If a₁ = 1, then a₅ = 3. However, this isn't possible because we need 4 integers between them, and a sum of 31.

If a₁ = 2, then a₅ = 6. Same problem as before.

If a₁ = 3, then a₅ = 9. This is a possible solution.

If a₁ = 4, then a₅ = 12. If we assume a₂ = 5, a₃ = 6, and a₄ = 7, then the sum is 34, so this is not a possible solution.

Therefore, Alex took 3 exams in his first year and 9 exams in his fifth year. So he took 19 exams total in his second, third, and fourth years.

3 < a₂ < a₃ < a₄ < 9

If a₂ = 4, then a₃ = 7 and a₄ = 8.

If a₂ = 5, then a₃ = 6 and a₄ = 8.

If a₂ = 6, then there's no solution.

So Alex must have taken 8 exams in his fourth year.

4 0

3 years ago

Enter the values for the highlighted variables that show how to subtract the rational expressions correctly:

sladkih [1.3K]

The highlighted variables a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

<h3>What is an Expression ?</h3>

An expression is a mathematical statement which consists of variables , constants and mathematical operators.

$\rm \dfrac{2}{x^2-36}-\dfrac{1}{x^2+36}\\= \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\=\dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{x(x+6)(x-6)}\\\\=\dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\=\dfrac{g}{x(x-6)}$

In the given expression

a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

To know more about Expression

brainly.com/question/14083225

#SPJ1

8 0

2 years ago

What is 2x+3x+x+9 simplified

murzikaleks [220]

6x+9 hope this helps

4 0

3 years ago

Read 2 more answers