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3 years ago

6.

Mathematics

1 answer:

Readme [11.4K]3 years ago

6 0

<span>Any ordered pair in a system that makes all the equations true

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The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi

Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

$P(X=x)=(_{x}^{n})\ p^xq^{n-x}$

$P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009$

$P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097$

$P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043$

$P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117$

$P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205$

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0

2 years ago

Read 2 more answers

A certain kind of bacteria multiplies at a rate of 150 percent per hour. When a person’s blood has 45,000,000 of these bacteria,

DIA [1.3K]

Initial number of Bacteria = Ao = 100
Number of Bacteria which make the person ill = A = 45,000,000

Growth rate = r = 150% = 1.50

The equation model for this situation is:

$A= A_{o}(1+r)^{t}$

Using the values in above equation, we can write:

$45000000=100(1+1.5)^{t} \\ \\ 
450000=(2.5)^{t} \\ \\ 
log(450000)=log((2.5)^{t}) \\ \\ 
log(450000)=t*log(2.5) \\ \\ 
t= \frac{log(450000)}{log(2.5)} \\ \\ 
t=14.21$

This means, the person will fall sick after about 14 hours.

8 0

3 years ago

Read 2 more answers

Makayla has 5 yards of ribbon to use for a craft project. She cuts the ribbon into pieces that are yard long.

jolli1 [7]

Answer:

Step-by-step explanation:

If she has 5 yards and she cuts them into 1/4 each. You're basically multiplying 5 by 4, and that's 20.

7 0

2 years ago

What is the word form for 2.35?

Afina-wow [57]

The word form for 2.35 is
"two point three five".

8 0

3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago