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Naily [24]
3 years ago
8

Please expand equation 0.5(5x - 2.2)

Mathematics
2 answers:
earnstyle [38]3 years ago
6 0
.5*5x
.5*-2.2
This should be right.
Andrews [41]3 years ago
5 0
0.44............is your answer
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Hi help with these please and thank yu? :)
ryzh [129]

Answer:

the first one is A

b/c when you calculate it comes 0 = 6

And the second one is D

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7 0
3 years ago
Help me with this question!!
laila [671]

Answer:

(-4, 2.5)

Step-by-step explanation:

that's where they intersect

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An electronic store makes a profit of 25$ for every portable DVD player sold and $55 for every DVD recorder sold. The managers t
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Cx+b=3(x-c) solve for x
Dafna11 [192]
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5 0
3 years ago
Read 2 more answers
Multiply: 4x * root(3, 4x ^ 2) * (2 * root(3, 32x ^ 2) - x * root(3, 2x))
Salsk061 [2.6K]

Answer:

32 {x}^{2} \sqrt[3]{ 2x }    -8{x}^{3}

Step-by-step explanation:

We want to

4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} }  - x \sqrt[3]{2x} )

We expand to obtain:

4x \sqrt[3]{4 {x}^{2} }  \times 2 \sqrt[3]{32 {x}^{2} }  -4x \sqrt[3]{4 {x}^{2} } \times  x \sqrt[3]{2x} )

We now simplify

8x \sqrt[3]{4 {x}^{2}  \times 32 {x}^{2} }    -4 {x}^{2}  \sqrt[3]{4 {x}^{2}  \times 2x}

We multiply the radicand

8x \sqrt[3]{64 \times {x}^{3}  \times 2x }    -4 {x}^{2}  \sqrt[3]{8 {x}^{3}}

Or

8x \sqrt[3]{ {(4x)}^{3}  \times 2x }    -4 {x}^{2}  \sqrt[3]{{(2x)}^{3}}

We take cube root to get:

8x  \times 4x\sqrt[3]{ 2x }    -4 {x}^{2}  \times 2x

We multiply out to get:

32 {x}^{2} \sqrt[3]{ 2x }    -8{x}^{3}

6 0
3 years ago
Read 2 more answers
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