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3 years ago

Please expand equation 0.5(5x - 2.2)

Mathematics

2 answers:

earnstyle [38]3 years ago

6 0

.5*5x
.5*-2.2
This should be right.

Andrews [41]3 years ago

5 0

0.44............is your answer

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Hi help with these please and thank yu? :)

ryzh [129]

Answer:

the first one is A

b/c when you calculate it comes 0 = 6

And the second one is D

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3 years ago

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laila [671]

Answer:

(-4, 2.5)

Step-by-step explanation:

that's where they intersect

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nasty-shy [4]

I believe it should be d

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3 years ago

Cx+b=3(x-c) solve for x

Dafna11 [192]

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3 years ago

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Multiply: 4x * root(3, 4x ^ 2) * (2 * root(3, 32x ^ 2) - x * root(3, 2x))

Salsk061 [2.6K]

Answer:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

Step-by-step explanation:

We want to

$4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} } - x \sqrt[3]{2x} )$

We expand to obtain:

$4x \sqrt[3]{4 {x}^{2} } \times 2 \sqrt[3]{32 {x}^{2} } -4x \sqrt[3]{4 {x}^{2} } \times x \sqrt[3]{2x} )$

We now simplify

$8x \sqrt[3]{4 {x}^{2} \times 32 {x}^{2} } -4 {x}^{2} \sqrt[3]{4 {x}^{2} \times 2x}$

We multiply the radicand

$8x \sqrt[3]{64 \times {x}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{8 {x}^{3}}$

$8x \sqrt[3]{ {(4x)}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{{(2x)}^{3}}$

We take cube root to get:

$8x \times 4x\sqrt[3]{ 2x } -4 {x}^{2} \times 2x$

We multiply out to get:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

6 0

3 years ago

Read 2 more answers