What solid is formed when rotating a square about a horizontal or vertical axis through the center of the square?
1 answer:
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Answer:
y = x + 1
Step-by-step explanation:
1) First, find the slope of the line between the two points. Whichever option has the same slope would be the right answer. To find this, use the slope formula .
and
represent the x and y values of one point, and
and
represent the x and y values of another point.
So, use the points given to answer the question. Substitute 4 for , 5 for
, 8 for
, and 9 for
then solve:
Therefore, the slope is 1.
2) Any line that is in a "y = a number" format is a horizontal line, and all horizontal lines have a slope of 0 - so the second option can't be the answer.
The rest of the options are in slope-intercept form, or y = mx + b format. Remember that the coefficient of the term with the x is the slope. Knowing this, y = x + 1 would need to be the answer since the coefficient of the term with the x is 1, and we already calculated that the slope is 1.
In a right angle, the sum of the squares of the two shorter sides is equal to the square of the longest side.
Here, the longest side is 25, the shorter sides are x and x+5.
The length of a side must be a positive number, so x=15.
The answer is C.
Here, the longest side is 25, the shorter sides are x and x+5.
The length of a side must be a positive number, so x=15.
The answer is C.