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mr Goodwill [35]
2 years ago
10

(05.02)

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
4 0

Answer:

y = x + 1

Step-by-step explanation:

1) First, find the slope of the line between the two points. Whichever option has the same slope would be the right answer. To find this, use the slope formula \frac{y_2-y_1}{x_2-x_1}. x_1 and y_1 represent the x and y values of one point, and x_2 and y_2 represent the x and y values of another point.

So, use the points given to answer the question. Substitute 4 for x_1, 5 for y_1, 8 for x_2, and 9 for y_2 then solve:

\frac{(9)-(5)}{(8)-(4)} \\= \frac{9-5}{8-4} \\= \frac{4}{4} \\= 1

Therefore, the slope is 1.

2) Any line that is in a "y = a number" format is a horizontal line, and all horizontal lines have a slope of 0 - so the second option can't be the answer.

The rest of the options are in slope-intercept form, or y = mx + b format. Remember that the coefficient of the term with the x is the slope. Knowing this, y = x + 1 would need to be the answer since the coefficient of the term with the x is 1, and we already calculated that the slope is 1.

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Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938


Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
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a bag of grapes weighs 5/8 of a pound. Before any was eaten, the bag of grapes weighed 4 times this amount. What is the weight o
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IceJOKER [234]

Answer:

y = -6x — 13

Step-by-step explanation:

use y = mx + b equation and plug in what you know.

5 = -6(-3) + b —> solve for b

b = -13 —> plug in what you know into y=mx+b

ANSWER: y = -6x — 13

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Answer:

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Step-by-step explanation:

3 0
3 years ago
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Need help fast!!! 15 points!!
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Answer:

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