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4 years ago

What is 9/15 in simplest form?

Mathematics

2 answers:

weqwewe [10]4 years ago

7 0

(9/15) = (3/15)

If you divide both the top and bottom of the fraction, (9/15), by 3, you get (3/5).

Alex73 [517]4 years ago

4 0

3/5
3 goes into 9 , 3 times
3 goes into 15 , 5 times

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144

Step-by-step explanation:

You need to know the Order of Operations. First you do 2 to the power of 4 (because it's the E in PEMDAS) which is 2*2*2*2 which equals 4, 8, 16, then you would do three squared which is 3*3 which equals 9. Multiply (M in PEMDAS) 16 by 9 which would come out to 144 or how I would multiply those two numbers is 9*10 + 9*6 or 90 + 54 with a final answer of 144.

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3 years ago

Graph the line for y+1=−3/5(x−4) on the coordinate plane.

lyudmila [28]

Answer:

y=-3/5x+7/5

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4 years ago

Super Bowl XLVI was played between the New York Giants and the New England Patriots in Indianapolis. Due to a decade-long rivalr

Diano4ka-milaya [45]

Answer:

Probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is 0.02385.

Step-by-step explanation:

We are given that Due to a decade-long rivalry between the Patriots and the city's own team, the Colts, most Indianapolis residents were rooting heartily for the Giants. Suppose that 90% of Indianapolis residents wanted the Giants to beat the Patriots.

Let p = % of Indianapolis residents wanted the Giants to beat the Patriots = 90%

The z-score probability distribution for proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = % of Indianapolis residents who were rooting for the Giants in Super Bowl XLVI in a sample of 200 residents = $\frac{170}{200}$ = 0.85

n = sample of residents = 200

So, probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is given by = P( $\hat p$ < 0.85)

P( $\hat p$ < 0.85) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.85-0.90}{\sqrt{\frac{0.85(1-0.85)}{200} } }$ ) = P(Z < -1.98) = 1 - P(Z $\leq$ 1.98)