Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:
This results in x = 3 and x = -2. The equation is true for these two x-values.
Start by writing what is said:
2x + 4 = -6
From there just solve for x:
Subtract 4 from both sides
2x + 4 - 4 = -6 - 4
2x = -10
Divide by 2 to get x by itself
2x/2 = -10/2
x = -5
To do this subtract 2 from each side of the equation to get y = -5, so the value of y in this is -5. Hope this helps!
Answer:
10
Step-by-step explanation:
