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Irina-Kira [14]
4 years ago
15

This is the last one please help me​

Mathematics
2 answers:
Salsk061 [2.6K]4 years ago
6 0

Answer:

Step-by-step explanation:

Area of shaded region = Area of Square - [ 2*area of semicircles + area of rectangle]

Square:

side = 9 m

Area = Side * side = 9*9 = 81 m²

Rectangle:

length = 10 m

width = 2 m

Area = length * width

       = 10 * 2

        = 20 m²

Semicircle:

diameter = 6 m

r = 6/2 = 3 m

Area of semicircle = πr²/2

Area of two semicircles = 2* πr²/2 = πr²

 = 3.14 * 3 *3

= 28.26 m²

Area of shaded region = 81 - [ 20 + 28.26]

                                       = 81 - 48.26

                                       = 32.74 m²

snow_lady [41]4 years ago
4 0
Are you finding area or perimeter of area then it’s 71 if it’s perimeter then it’s 54
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Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours

547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000

x = no. of times owner-occupied units had a water supply stoppage.

<h3>What is the probability at x =0?</h3>

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P(x=0) = 0.0370

Similarly, we have at x=1

P(x=1) = 5012000/14770000

P(x=1) = 0.3393

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P(x=4) = 557000/14770000

P(x=4) = 0.0378

x           f(x)

0             0.0370

1              0.3393

2         0.4137

3              0.1722

4         0.0378

Total     1

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

To learn more about the probability distribution visit:

brainly.com/question/24756209

#SPJ1

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