Amount of pizza eaten by Charlie.
7/6× 22/7 × (101/2)² =9350.91667
Amount of pizza eaten by Julie
5/12 × 22/7 × 90.5² = 10725.3273
Answer = Julie
I feel really bad for you. This looks like a death problem
To solve this problem you must apply the procceddure shown below:
1. You have the following system of equations:
<span>
x+y = 3
2x–y = 6
2. Then, you must clear the variable y from the first equation and susbtitute it into the second equation, as below:
x+y=3
y=3-x
2x-y=6
2x-(3-x)=6
2x-3+x=6
3x=6+3
3x=9
3. Therefore, the value of x is:
x=9/3
x=3
4. As you can see, the correct answer is:
x=9
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First we make the fractions homonym ( they must have the same denomitator)
0.6 = 6 / 10 7/9
6/10 = 6 * 9 / 10 * 9 = 54 / 90 7/9 = 7 * 10 / 9 * 10 = 70 / 90
The numbers which are between these numbers are ;
55 / 90 , 56 / 90 , 57 / 90 , 58 / 90 , 59 / 90, 60 / 90 , 61 / 90 , 62 / 90 , 63 / 90 , 64 / 90, 67 / 90 , 68 / 90 , 69 / 90
62 / 90 = 62 / 2 / 90 /2 = 31 / 45
So the right answer is B.
Hope that helps :)
The Expected value of a draw from the given question is; A; 0.77
We are told the face cards are K, Q, J. This means that there are 3 face cards for each of the 4 suits.
Since you earn 10 points for each face card, it means that;
total possible gain = 10 × 3 × 4 = 120
In a deck of cards, there are a total of 52 cards.
This means that;
Number of cards that are not K, Q or J = 52 - (4 × 3) = 40
Since 2 points are lost for drawing any of this 40 cards, then;
Total possible loss = 40 × 2 = 80
Expected gain = 120 - 80
Expected gain = 40
Expected value of a draw = 40/52
Expected value of a draw = 0.77
Read more about expected value at; brainly.com/question/1450915