$45
If u need to show work do 250 x .18
*if u don’t mind brainliest answer pls
Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
1. 4
2.4
3.3
4.2
5.2
6.what after the plus
7.3
8.
Answer:
you would need to first do
(p times 1.25)
+
(j times 1.85)
and then
22 divided by 33.50
Step-by-step explanation:
Answer:
2 x^3
Step-by-step explanation:
sqrt(12 x^8)/ sqrt(3x^2)
combine into 1 term
sqrt(12x^8/3x^2)
when dividing exponents with the same base, we subtract
sqrt(12/3 x^(8-2))
sqrt(4 x^6)
sqrt(4) sqrt(x^6)
2 x^3
