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balu736 [363]
3 years ago
13

A certain type of bacteria doubles in population every hour. Their growth can be modeled by an exponential equation. Initially,

there are 15 bacteria colonies present in the sample.
A. Find an equation to model the bacteria growth.
B. How many colonies are present after 3 and a half hours?
C. When will there be 584 colonies present?
Mathematics
1 answer:
Nastasia [14]3 years ago
7 0
    <span> A: y=2x 15 (or whatever variables you choose to represent the colony growth and time)

B: y=2(3.5) 15;
22 colonies

C: substitute 584 with y into the original equation, so:
584=2x 15
569=2x
284.5=x; therefore, after 284.5 hours</span> Hope this helps! :D
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You pay 1.5% interest on your credit card bill every month. This month your
IrinaVladis [17]

Answer:

Step-by-step explanation:

Bill=3475

Interest=1.5%

Total payment made=3475+3475x1.5/100

=3475x101.5/100

=3527.125$ is the total payment (answer)

4 0
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Type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. find the missing te
Allisa [31]

The missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have the roots of a quadratic equation:

5 ± 3i

To find the quadratic equation:

(x - (5+3i))(x - (5-3i))

\rm =x^2+x\left(-\left(5-3i\right)\right)-\left(5+3i\right)x-\left(5+3i\right)\left(-\left(5-3i\right)\right)

= x² -10x + 34

The missing value is 10x

The quadratic equation is:

= x² -10x + 34

Thus, the missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.

Learn more about the complex number here:

brainly.com/question/10251853

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6 0
2 years ago
Please help ill give you brainliest
SVEN [57.7K]
The first one is 154

The second one is 12.65^2
3 0
3 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
URGENT PLS PLS HELP WILL GIVE BRAINLIEST!!
SSSSS [86.1K]

Answer:

the second graph is likely the continuous one because the first graph stops on the x-axis

6 0
3 years ago
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