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Makovka662 [10]
3 years ago
14

Yoko has scored 81 , 84 , 84 , 69 , and 76 on her previous five tests. What score does she need on her next test so that her ave

rage (mean) is 81 ?
Mathematics
1 answer:
kkurt [141]3 years ago
7 0
Took must make a 92 on the next test.
(81+84+84+69+76+x)/6=81
(394+x)/6=81
Multiply by 6 on both sides
394 + x = 486
Subtract 394 from both sides.
x= 92
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Based on historical data, your manager believes that 41% of the company's orders come from first-time customers. A random sample
TEA [102]

Answer:

The probability that the sample proportion is between 0.35 and 0.5 is 0.7895

Step-by-step explanation:

To calculate the probability that the sample proportion is between 0.35 and 0.5 we need to know the z-scores of the sample proportions 0.35 and 0.5.

z-score of the sample proportion is calculated as

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of first time customers
  • p is the proportion of first time customers based on historical data
  • N is the sample size

For the sample proportion 0.35:

z(0.35)=\frac{0,35-0.41}{\sqrt{\frac{0.41*0.59}{72} } } ≈ -1.035

For the sample proportion 0.5:

z(0.5)=\frac{0,5-0.41}{\sqrt{\frac{0.41*0.59}{72} } } ≈ 1.553

The probabilities for z of being smaller than these z-scores are:

P(z<z(0.35))= 0.1503

P(z<z(0.5))= 0.9398

Then the probability that the sample proportion is between 0.35 and 0.5 is

P(z(0.35)<z<z(0.5))= 0.9398 - 0.1503 =0.7895

6 0
3 years ago
Solve the proportion<br> h/4=7/14
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14*h = 7*4
14h=28
divide by 14 on both sides
h=28/2=2
4 0
2 years ago
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