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Makovka662 [10]
4 years ago
15

Ok so this is so confusing The volume of water in a rectangular swimming pool can be modeled by the polynomial 2x3 _ 9x2 + 7x +

6. If the depth of the pool is given by the polynomial 2x + 1, what polynomials express the length and width of the pool? Why couldn't they just give me the volume?
Mathematics
1 answer:
Alika [10]4 years ago
6 0
The volume formula is V= l x L x H, l=width, L=Length, H= Depth, so 
2x3 _ 9x2 + 7x + 6 = l x L x (2x + 1), because H=(2x + 1), so 
l x L= (2x3 _ 9x2 + 7x + 6 )/ (2x + 1) = (2x3 _ 9x2 + 7x + 6 ) X [1/(2x + 1)]
case1: l= (2x3 _ 9x2 + 7x + 6 ) or L= 1/(2x + 1), case2: L= (2x3 _ 9x2 + 7x + 6 ) or l= 1/(2x + 1)
the why question:
perhaps there is similarity of value between volume and l, or volume and L
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3 years ago
The area of a rectangle is equal to its length times its width. If the area of a rectangle is 4x +20 which options could be the
nydimaria [60]

Answer:

The required option are

Length = 4 and width = x+5

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This can also be written as

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5 0
3 years ago
If the discriminant of an equation is zero, which of the following is true of the equation?​
White raven [17]

\sf Your \: question \: is \: incomplete. \:

______________________

\sf \: I \: believe \: this \: is \: the \: answer \: you \: wanted ⟹

\sf If  \: the  \: discriminant  \: of \:  an \:  equation \:  is  \: zero, \: then \\  \sf \: the \: equation \: will \: have \:\underline{ 1 \: real \: solution \: with \: real \: and \: equal \: roots}.

\boxed{ \sf{Explanation}}

\sf If \: discriminant \: of \: quadratic \: equation  \: ax^{2} + bx + c \: \\ \sf is \: b^{2} - 4ac = 0 \: then \: it \: will \: have \\ \sf↦\underline{1 \: real \: solution \: with \: real \: and \: equal \: roots.}

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Find the area and perimeter of the shape below. Help plzzz.
kozerog [31]
Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
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A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
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A=l*w
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A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
4 0
4 years ago
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