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3 years ago

Need Help asap Choices 9 18 60 120

Mathematics

1 answer:

Bad White [126]3 years ago

8 0

120 is the right answer that is what my teacher told me

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Shawn found that a solution of x = 3 was extraneous for his function. What would be a possible denominator in Shawn's function?

Alex_Xolod [135]

Your answer is B. x2 -2x -3

Hope this helps!!

6 0

3 years ago

Read 2 more answers

Given the equation

tatiyna

Answer:

A. Subtract x from both sides: (i.e. 5+x-12 = x-7 <--> 5-12 = -7)

This equation is identically true, so it holds no matter what x is.

B. This one is pretty self-explanatory

Step-by-step explanation:

u wrote the question wrongly the answer is in answer box

This question also my teacher gives me

hope it helps

8 0

3 years ago

When I evaluate m=2 , h=1 then what would mh+3 would be?

Andrei [34K]

Answer:5

Step-by-step explanation: since you know that m=2, and h=1, mh is the same as m × h, or 2×1. Which is equal to 2, you then add 3 to get your answer

7 0

3 years ago

Please help picture shown !!!!

never [62]

Right... soo wouldnt the a: be E??

7 0

3 years ago

A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe

Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job = $6+14 =20\ hrs$

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

$\frac{6}{18}+\frac{20}{a}=1$

By reducing the fraction we get;

$\frac{1}{3}+\frac{20}{a}=1$

Now we will make the denominator common to solve the fraction we get;

$\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1$

Now denominators are same so we will solve the numerator we get;

$\frac{a+60}{3a}=1$

Multiplying both side by 3a we get;

$\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a$

Combining the like terms we get;

$3a-a=60\\\\2a=60$

Dividing both side by 2 we get;

$\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs$

Hence the apprentice can complete the job in 30 hours by working alone.

4 0

3 years ago