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3 years ago

WILL MARK BRAINLIEST!!! What is a net pay???

Mathematics

1 answer:

seropon [69]3 years ago

8 0

Answer:

Net pay is what you get after you pay taxes.

Step-by-step explanation:

Gross pay is before taxes and deductions.

Net pay is what you are left with after they deduct taxes.

gross pay = $300

- taxes = $50

net pay = $250

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A ship is anchored off a long straight shoreline that runs north and south. From two observation points 16 miles apart on shore,

ELEN [110]

D - the shortest distance from the ship to the shore.
d / ( 17 - x ) = tan 32° = 0.62487
d / x = tan 53° = 1.32704
d = 0.62487 ( 17 - x )
d = 1.32704 x
0.62487 ( 17 - x ) = 1.32704 x
10.62279 - 0.62487 x = 1.32704 x
x = 10.62279 : 1.95191
x = 5.44226 miles
d = 5.44226 · 1.32704
Answer:
d = 7.222 miles

6 0

3 years ago

The amount of money (in dollars) that it costs to purchase x square feet of carpet is given by f(x)=7.5x. The installation fee i

Lady bird [3.3K]

Answer:

Refer below

Step-by-step explanation:

Installation fee equation will be added onto the original equation

So g = base cost + percent cost + $100

(Cost of carpet) ---> g = $7.5x + ($7.5x * 0.05) + $100

Plug in 150 into the formula that gives you $1281.25

Make sure to study these, questions like these will for sure strengthen your math skills

6 0

3 years ago

Read 2 more answers

Paul wants to compare whether the prices of tangerines in two supermarkets differ significantly. He has been noting down the dai

Wewaii [24]

<span>Based on the rules of statistics</span>

68% of the data falls within 1 standard deviation of the mean

95% of the data falls within 2 standard deviation of the mean

99% of the data falls within 3 standard deviation of the mean

20 falls between the range of -56 to 56 (from the given 95%)

Hence we accept the null hypothesis; else, if the mean falls outside the range, we reject the null hypothesis.

5 0

3 years ago

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

7 0

3 years ago

SOLVE APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK. a) A rectangle with perimeter 18 cm has l

alekssr [168]

Answer:

$w=2\\l=7$

Step-by-step explanation:

$l+l+w+w=18\\\\2w+3=l\\\\2w+3+2w+3+w+w=18\\6w+6=18\\6w=12\\w=2\\\\2w+3=l\\2*2+3=l\\4+3=l\\l=7$

4 0

3 years ago

Read 2 more answers