This is how you work it out:
u + xy
Plug in your numbers that you know:
20 + 9 * 8
20 + 72
92
Answer:
45x-95
Step-by-step explanation:
Answer:
7x65 is 455
Step-by-step explanation:
I need more info if this does not workout...
Answer:
![(f\circ h)(2)=2](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%282%29%3D2)
Step-by-step explanation:
<u>Composite Function
</u>
Given f(x) and h(x) real functions, the composite function named
is defined as:
![(f\circ h)(x)=f(h(x))](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%28x%29%3Df%28h%28x%29%29)
It can be found by substituting h into f.
We are given the functions:
![f(x)=2x^2-9x+2](https://tex.z-dn.net/?f=f%28x%29%3D2x%5E2-9x%2B2)
![h(x)=x^2-4](https://tex.z-dn.net/?f=h%28x%29%3Dx%5E2-4)
It's required to find ![(f\circ h)(2)](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%282%29)
As defined above:
![(f\circ h)(x)=f(h(x))](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%28x%29%3Df%28h%28x%29%29)
Thus:
![(f\circ h)(2)=f(h(2))](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%282%29%3Df%28h%282%29%29)
Find h(2):
![h(2)=2^2-4=0](https://tex.z-dn.net/?f=h%282%29%3D2%5E2-4%3D0)
h(2)=0
Now:
![(f\circ h)(2)=2(0)^2-9(0)+2](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%282%29%3D2%280%29%5E2-9%280%29%2B2)
![(f\circ h)(2)=2](https://tex.z-dn.net/?f=%28f%5Ccirc%20h%29%282%29%3D2)
The surface area of a cylinder is the sum of the top + bottom + body, right?
The top and the bottom are circles with the same radius 3.5 . And we know that the area of a circle is r^2pi, (don't forget we have 2 circle, so, the answer must be multiplied by 2)
Now, the body: the body is just a rectangular with the width is the height of the cylinder and the length is the circumference of the circle.
The circumference = 2 r pi
the height is given
All you need to do is to calculate them and add them up. You need to work out to get the answer.