First: f(2) is same as f(x=2) so all we have to do is to express x=2 in f(x)
f(2) = 3*2 + 2 = 8
Second
f^(-1) (3) is inverse function. first we solve f(x) for x.
let f(x) be equal to some variable m
m = (2x -7)/3
3m = 2x - 7
2x = 3m + 7
x = (3m + 7)/3
now we write:
f^-1(x) = (3x + 7)/3
x=3
f^-1(3) = 16/3
Third
2y + 14 = 4y - 2
we just solve for y
2y = 16
y = 8
Now we take that f(x) = y because we both write to be the functions of x
that means that First and third have same result.
~ Simplifying
-4x + -4 = -7(x + 4)
~ Reorder the terms:
-4 + -4x = -7(x + 4)
~ Reorder the terms:
-4 + -4x = -7(4 + x)
-4 + -4x = (4 * -7 + x * -7)
-4 + -4x = (-28 + -7x)
~ Solving
-4 + -4x = -28 + -7x
~ Solving for variable 'x'.
~ Move all terms containing x to the left, all other terms to the right.
~ Add '7x' to each side of the equation.
-4 + -4x + 7x = -28 + -7x + 7x
~ Combine like terms: -4x + 7x = 3x
-4 + 3x = -28 + -7x + 7x
~ Combine like terms: -7x + 7x = 0
-4 + 3x = -28 + 0
-4 + 3x = -28
~ Add '4' to each side of the equation.
-4 + 4 + 3x = -28 + 4
~ Combine like terms: -4 + 4 = 0
0 + 3x = -28 + 4
3x = -28 + 4
~ Combine like terms: -28 + 4 = -24
3x = -24
~ Divide each side by '3'.
x = -8
~ Simplifying
x = -8
Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i
The additive inverse of the complex number a + bi is -(a+bi) = -a - bi
In this case, a = -8 and b = 3i
a + bi = -8 + 3i
additive inverse is: -(-8+3i) = +8 - 3i
The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.
</span>
Answer: 77/95 chance
Step-by-step explanation: There are 8+7+6+5+4+3+2+1 = 36 choices that differ by 12 or more, so the probability they differ by 12 or more is 36/190 = 18/95. So the probability that they do not differ by 12 or more is 1 - 18/95 = 77/95. Brainliest please?
36.96 with the formula 0.24 * 154 = 36.96
