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harina [27]
3 years ago
9

A sphere has a radius of 11 feet. A second sphere has a radius of 8 feet. what is the difference of the volume of the spheres

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

1092π ft³  

Step-by-step explanation:

The formula for the volume of a sphere is

V = ⁴/₃πr³

1. Volume of larger sphere

V₁ = ⁴/₃π (11)³ = ⁴/₃π × 1331 = 1774⅔π ft³

2. Volume of smaller sphere

V₂ = ⁴/₃π (8)³ = ⁴/₃π × 512 = 682⅔π ft³

3. Difference of volumes

V₁ - V₂ = 1774⅔π ft³ - 682⅔π ft³ = 1092π ft³ ≈ 3431 ft³

The difference of volumes of the spheres is 1092π ft³.

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Answer:

The standard equation of the sphere is (x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

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Hence,

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

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Now, we will determine the distance (diameter) of the sphere

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d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2}      }

d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}

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d = \sqrt{16 +196 + 0

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To find the radius, r

From Radius = \frac{Diameter}{2}

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r = \sqrt{53}

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Radius of the sphere is \sqrt{53}

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(x-h)^{2} + (y-k)^{2} + (z-l)^{2}  = r^{2}

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