Question

PLEASE HELP!

Answer 1

Answer:

A

Step-by-step explanation:

We are given that a function

$f(x)=x^2+8x+6$

We have to find the next step in the process and what is the extreme value .

By adding and subtracting 16  then we get

$f(x)=(x^2+8x+16)+6-16$

$f(x)=(x+4)^2-10$

By using the formula

$(a+b)^2=a^2+b^2+2ab$

The given function is the equation of parabola .

By comparing  with

$y=(x-h)^2+k$

Where vertex=(h,k)

Vertex=(h,k)=(-4,-10)

Substitute x=-4

Then, we get

$f(x)=-10$

Hence, the extreme minimum value of function =-10

Option A is true.