You don't list the "sums listed below" but I can still help you.
There are 6 ways to get a sum of 7 using a pair of dice:
1+6
6+1 You might be asking why 2+5 isn't the same as 5+2
2+5 Imagine the dice are different colors. Is a red 2 and green 5 the
5+2 same as a green 2 and red 5? (No, it's not)
3+4
4+3
You need two numbers that also provide 6 ways to win. One pair that would work is 11 and 9 There are two ways to make 11 (5+6) and (6+5) and there are four ways to make 9 (3+6), (6+3) (4+5) and (5+4) - that's a total of six ways. So to balance your friend's 7 - you could go for sums of 11's and 9's. Check the choices you were given and find the numbers (it could be three numbers like 2,3, and 12) that give you 6 ways to win.
Here are the numbers and their ways
Sum of the dice Ways to get it
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
Y = -1
1 - 13(-1)
= 1 - (-13)
= 14
Answer:
his is the format of the straight-line equation,
Where, y = mx + c
Here, m = slope
c = y-intercept.
You usually get coordinates, and after solving, we get our result as an equation of the line.
Hope this helps!
Step-by-step explanation:
Answer:
Group A, IQR = 700
GROUP B, IQR =.450
Group A's IQR is greater
The values in the middle 50%.of Group A are more spread out Than those of Group B.
Step-by-step explanation:
Data for.each group :
The IQR = Q3 - Q1
From the boxplot :
Group A:
Q1 = 1100 ; Q3 = 1800
IQR = 1800 - 1100 = 700
Group B:
Q1 = 1400; Q3 = 1850
IQR = 1850 - 1400 = 450
Greater IQR = Group A
The values in the middle 50%.of Group A are more spread out Than those of Group B.
Answer: 34*12 = 34(10+2) = 340 +68 = $408
And $408 is close to $434.
