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valina [46]
3 years ago
14

does anyone know how to solve (and find the domain) a math problem like this: (7^5-x)^6-x = 49 (pls include explanation I have a

lot more of these problems) also pls don't cheese me for the pts
Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

his is the format of the straight-line equation,

Where, y = mx + c

Here, m = slope

c = y-intercept.

You usually get coordinates, and after solving, we get our result as an equation of the line.

Hope this helps!

Step-by-step explanation:

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Nina [5.8K]
The answer is B.
X = -11 :-)
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3 years ago
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Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
Find the unit rate. 927 pages in 9 days=__pages per day
Zina [86]
The answer is 103 pages/day
This is bcz 927 divided by 9= 103

Hope this helps and good luckkkk :)
6 0
2 years ago
Any help on this please ?
dlinn [17]

Answer:

(0,-5), I believe.

Step-by-step explanation:

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ZanzabumX [31]

Answer:

8×+6×-5×{2}

8×+6×-10×

14×-10×

4×

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2 years ago
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