If a triangle measures 180 degrees one side is 29 the other side is 20 and the last side is B what is the measure for B

Juno calculated the area of a square to be 4/9 square yard. Which shows the side length of the square?

Stella [2.4K]

$\bf \textit{area of a square}\\\\
A=s^2~~
\begin{cases}
s=side's~length\\
--------\\
A=\frac{4}{9}
\end{cases}\implies \cfrac{4}{9}=s^2
\\\\\\
\sqrt{\cfrac{4}{9}}=s\implies \cfrac{\sqrt{4}}{\sqrt{9}}=s\implies \cfrac{2}{3}=s$

3 0

3 years ago

The ages of three family children can be expressed as consecutive integers. the square of the age of the youngest child is 4 mor

sukhopar [10]

Let the middle child be x
youngest child = x - 1
Oldest child = x + 1

(x - 1)^2 = 8(x + 1) + 4
x^2 - 2x + 1 = 8x + 8 + 4
x^2 - 10x - 11 = 0
(x - 11) * (x + 1) = 0

X = - 1 makes no sense. How can a middle child be - 1 years old?
x = 11

The youngest child is 10
The middle child is 11
The oldest child is 12

Check
=====
10^2 = 100
(8*12) + 4
96 + 4 = 100 So the results have been checked.

3 0

3 years ago

A real-estate agent conducted an experiment to test the effect of selling a staged home vs. selling an empty home. To do so, the

Genrish500 [490]

The statement "Yes, all the conditions for Inference have been met" is correct.

A t-test is a hypothesis-testing technique for analyzing the means of one or two populations. A t-test can be used to see if a single group differs from a known value, if two groups differ from each other (an independent two-sample t-test), or if paired measurements show a significant difference.

We have:

Null hypothesis:H0: μ1 – μ2 = 0,

Alternative hypothesis: Ha: μ1 – μ2 < 0

As it is mentioned that the samples are drawn randomly and mentioned that no skewness is observed, this Indicates that the distribution is approximately normal

The total number of readings = 10

Which is not more than 10% of the Population size.

Thus, the statement "Yes, all the conditions for Inference have been met" is correct.

Learn more about the t-test here:

brainly.com/question/15870238

6 0

2 years ago

Tanx-cotx / sinxcosx =sec^2-csc^2x. Please show all steps.

Katarina [22]

$\bf \cfrac{tan(x)-cot(x)}{sin(x)cos(x)}\implies \cfrac{\frac{sin(x)}{cos(x)}-\frac{cos(x)}{sin(x)}}{sin(x)cos(x)}\implies \cfrac{\frac{sin^2(x)-cos^2(x)}{cos(x)sin(x)}}{\frac{sin(x)cos(x)}{1}}
\\\\\\
\cfrac{sin^2(x)-cos^2(x)}{cos(x)sin(x)}\cdot \cfrac{1}{sin(x)cos(x)}\implies \cfrac{sin^2(x)-cos^2(x)}{cos^2(x)sin^2(x)}
\\\\\\
\textit{and now, we distribute the denominator}
\\\\\\
\cfrac{sin^2(x)}{cos^2(x)sin^2(x)}-\cfrac{cos^2(x)}{cos^2(x)sin^2(x)}\implies 
\cfrac{1}{cos^2(x)}-\cfrac{1}{sin^2(x)}$

and surely you know what that is

3 0

3 years ago

Pool measuring 10 ft by 20 feet will have a cement walkway around it. The area covered by the pool and the cement walkway is 600

ki77a [65]

Answer:the width of the walkway is 5 feet

Step-by-step explanation:

Let x represent the width of the walkway.

The pool measures 10 ft by 20. If the walkway must have a uniform width around the entire pool, then the total length of the pool and the walkway would be 10 + x + x = 10 + 2x

The total width of the pool and the walkway would be 20 + x + x = 10 + 2x

The area covered by the pool and the cement walkway is 600 square feet. This means that

(10 + 2x)(20 + 2x) = 600

200 + 20x + 40x + 4x^2 = 600

4x^2 + 60x + 200 - 600 = 0

4x^2 + 60x - 400 = 0

Dividing through by 4, it becomes

x^2 + 15x - 100 = 0

x^2 + 20x - 5x - 100 = 0

x(x + 20) - 5(x + 20) = 0

(x - 5)(x + 20) = 0

x = 5 or x = - 20

The width cannot be negative. Therefore, the width of the walkway is 5 feet

8 0

3 years ago