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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
__
You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
_____
I like to use a graphing calculator for problems like this.
Answer:
The slope intercept form is y = mx + b, where b is the y-intercept. In the equation y = 2x - 1, the y-intercept is -1. So, if you have an equation like y = 4x, there is no "b" term. Therefore, the y-intercept is zero, and the line passes through
Answer:
120°.
Step-by-step explanation:
The sum of all interior angles in a polygon with 
sides (
, 
) is equal to 
. (Credit: Mathsisfun.)
The polygon here has 6 sides. 
. Its interior angles shall add up to 
.
Consider the properties of a regular polygon. (Credit: Mathsisfun.)
- All sides in a regular polygon are equal in length.
- All angles in a regular polygon are also equal.
There are six interior angles in a polygon with 6 sides. All six of them are equal. Thus, each of the six interior angle will be
.
8 for 6 is the answer I think
Answer:
y=-1/2x+4 Is your answer
Step-by-step explanation:
y=mx+b
3=2x+4
-1=2x
x=-1/2
You already know y is 4 so y=-1/2x+4
