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Delvig [45]
3 years ago
9

Please I need help ASAP!!!

Mathematics
1 answer:
lesantik [10]3 years ago
4 0

Answer:

First answer.

Step-by-step explanation:

This is called the Arc length, here is the formula:

Arc length = (angle/360)*(2Pi*radius)

So,

(45/360)*(2*3.14*4)

= 3.14

SO Pi !!!!!

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(4,-6) (3,-2) what is the slope
Olin [163]

Answer:

M = -4

Step-by-step explanation:

6 0
3 years ago
Karim is ordering video games. Each game costs $39.99, and there is a $4.85 shipping charge per order. How much will it cost him
weqwewe [10]
Given:
Cost of a game = $39.99
Shipping charge = $4.85
Let,
number of video games be "n"
Now,
total cost = (cost of each game * total no. of games) + shipping charge
               = $39.99n + $4.85

So, you use the above equation to find the total cost of video games.
7 0
3 years ago
What is the solution to the equation = 25?<br><br> x = 5<br> x = 10<br> x = 25<br> x = 125
Brilliant_brown [7]

Answer:

x=125

Step-by-step explanation:

To solve we must find a number that when divided by 5 equals 25.

To do this we can either...

Take each answer choice and plug in the value into the x spot and see if it works...

5/5=25  WRONG

10/5=25 WRONG

25/5=25 WRONG

125/5=25 CORRECT!

ORRR... we can set the equation so that the x is alone on one side.

To do this we can multiply both sides by 5

\frac{x}{5}=25 ---> x=25×5

x=125

7 0
2 years ago
The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.
evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}

b) P(population with IQ between 120 and 125.)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%

P(120 \leq x \leq 125) = 4.4\%

6 0
3 years ago
The answer to this question.
LekaFEV [45]

Answer:

.................................

3 0
3 years ago
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