By Pythagoras Theorem,
the length of the other leg= (63^2-52^2)^1/2
hope this helps :)
1 mi and 900 ft,1 mile = 5280 ft
69 - 3a = 0
69 - 3a (-69) = 0 (-69)
-3a = -69
-3a(/-3) = -69(/-3)
a = 23
hope this helps
Thank you for posting your question here. Please see below answers for the problem above:
a. to find the circumference of the tire you need to multiply 3.14 by 2.5:
= 3.14 x 2.5
= 7.85 to round of it will be 8
b. to get the number of times the tire have to rotate to travel 1 mile:
1 mile = 5,280 ft
1 rotation is 7.85
5,280/7.85 = 672.611465
