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Anna007 [38]
4 years ago
9

Which statement about the point (2, 0) is true?

Mathematics
2 answers:
svet-max [94.6K]4 years ago
8 0

It is on the X axis hope this helps

Veronika [31]4 years ago
7 0

Answer:

c

Step-by-step explanation:

x axis i took test

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Find the value of x and y (2y + 5)
Gekata [30.6K]

Answer:

The answer is: M= 2

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%5E2%3D16" id="TexFormula1" title="\sqrt{x} ^2=16" alt="\sqrt{x} ^2=16" align
inn [45]

Step-by-step explanation:

({ \sqrt{x} }^{2})  = 16 \\  \sqrt{x } =  \sqrt{16}   \\  \\ sqrt \: root  \: will \: be \: cancelled \\ so \:  \\ x \: \:  = 16

5 0
3 years ago
How do you solve for a and b showing your work
Mariulka [41]

Answer:

a) 4

b) \frac{1}{2} \sqrt{y^5}

Step-by-step explanation:

<u>PART A</u>

Simplify the expression by solving out the square roots.

\frac{\sqrt{16} \sqrt{p} }{\sqrt{p}} = \frac{4 \sqrt{p} }{\sqrt{p}}

You can cancel out the \sqrt{p} on the top and bottom.

So, a should be 4.

<u>PART B</u>

Solve out the square root. The square root is pretty much the 1/2 power, so you can divide the exponents by half.

\frac{\sqrt{y^{10}} }{\sqrt{4y^{5}} } = \frac{y^{5}}{2y^{\frac{5}{2}} }

You can subtract exponents to divide them. So the y variable becomes y^{5 - 5/2}, or y^{5/2}.

Then, the overall expression is \frac{1}{2} y^{\frac{5}{2} }, or you can turn that into \frac{1}{2} \sqrt{y^5}.

5 0
4 years ago
What is the correct answer???
lapo4ka [179]

Answer:

Step-by-step explanation:

The given equation passes through the origin:

y-0 = \frac{1}{4} (x-0) + 4

The segment passes through the point (-2,6)

So the equation will become (y-6) = \frac{1}{4} (x+2) +4

3 0
3 years ago
Please help me with this
Fudgin [204]

The perimeter of the rectangle is 2(2x+5), and the perimeter of the triangle is x+7+x+4+x+11, which simplifies to 3x+22.

Therefore...

3x+22=4x+10

x=12

The perimeter of the rectangle is 2(2(12)+5)=2(24+5)=2(29)=48.

a. x=12

b. The perimeter of each figure is 48.

5 0
3 years ago
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