<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%5E2%3D16" id="TexFormula1" title="\sqrt{x} ^2=16" alt="\sqrt{x} ^2=16" align

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Mrrafil [7]

2 years ago

="absmiddle" class="latex-formula">

Mathematics

1 answer:

inn [45]2 years ago

5 0

Step-by-step explanation:

$({ \sqrt{x} }^{2}) = 16 \\ \sqrt{x } = \sqrt{16} \\ \\ sqrt \: root \: will \: be \: cancelled \\ so \: \\ x \: \: = 16$

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The graph of the function g (x) = -3x2 + bx + 2 is shown. What is the value of b?

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Find the diamtere of a circle if its radius is 96.5cm

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$\huge \blue{\tt{Answer:}}$

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3 years ago

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A circle is centered at the point (-7, -1) and passes through the point (8, 7).The radius of the circle is____ units. The point

denis-greek [22]

Answer:

Part 1) The radius of the circle is r=17 units

Part 2) The points (-15,14) and (-15,-16) lies on this circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center of the circle and any point on the circle is equal to the radius of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(-7, -1) and (8, 7)

substitute

$r=\sqrt{(7+1)^{2}+(8+7)^{2}}$

$r=\sqrt{(8)^{2}+(15)^{2}}$

$r=\sqrt{289}$

$r=17\ units$

step 2

Find out the y-coordinate of point (-15,y)

The equation of the circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

substitute the values

$(x+7)^2+(y+1)^2=17^2$

$(x+7)^2+(y+1)^2=289$

Substitute the value of x=-15 in the equation

$(-15+7)^2+(y+1)^2=289$

$64+(y+1)^2=289$

$(y+1)^2=289-64$

$(y+1)^2=225$

square root both sides

$(y+1)=(+/-)15$

$y=-1(+/-)15$

$y=-1(+)15=14$

$y=-1(-)15=-16$

therefore

we have two solutions

point (-15,14) and point (-15,-16)

see the attached figure to better understand the problem

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3 years ago

Midpoint of ab if a=5 and b=19

Setler [38]

Midpoint formula
a + b/2

Plugin
5+19/2
24/2
12

The midpoint of ab is 12

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3 years ago

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