At first you would subtract 39 from 60. Then you would do 21/5.5 and you would get 3.818… and due to the fact you can't go over 60 you would round to 3 and not 4

8 0

3 years ago

Four congruent isosceles right triangles are cut from the 4 corners of a square with a side of 20 units. The length of one leg o

yanalaym [24]

Answer:

368 sq. units.

Step-by-step explanation:

We have a square of side lengths 20 units and we cut four congruent isosceles right triangles from the corners of the square.

Now, the four isosceles right triangles have one leg equal to 4 units.

Therefore, the area of four triangles = $4 \times ( \frac{1}{2} \times 4 \times 4) = 32$ sq. units.

Now, we have the area of the given square is (20 × 20) = 400 sq. units.

Therefore, the area of the remaining octagon will be (400 - 32) = 368 sq. units. (Answer)

7 0

3 years ago

Find the quotient of 2.632 · 104 and 2 · 10-7.

faust18 [17]

2.632 x 10^4 ÷ 2 x 10-7 =

1.316 x 10^11

5 0

3 years ago

Read 2 more answers

F(x) = x2 + 1 g(x) = 5-x (f+g)(x) = O x2 + x-4 x²+x+4 O x2-x+6 O x2 + x + 6

charle [14.2K]

Answer:

$\boxed{(f + g)(x) = {x}^{2} - x + 6}$

Given:

$f(x) = {x}^{2} + 1 \\ \\ g(x) = 5 - x$

To Find:

$(f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$= > f(x) + g(x) = ({x}^{2} + 1) + (5 - x) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 1 + 5 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 6 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - x + 6$

5 0

3 years ago