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2 years ago

12

The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it r

ained that day or not. Given that it was less than 80º on a given day, what is the probability that it also rained that day?

2 answers:

Alisiya [41]2 years ago

7 0

What is the probability that it also rained that day answer 0.3

Sergio039 [100]2 years ago

6 0

Answer:0.3

Step-by-step explanation:

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A culture started with 1,000 bacteria. After 4 hours, it grew to 1,100 bacteria. Predict how many bacteria will be present after

max2010maxim [7]

Answer:

1,300

Step-by-step explanation:

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2 years ago

What is the length of one side of a regular octagon if its perimeter is 208 mm?

marin [14]

Well if you know the top and the bottom are equal and the two sides are equal. So just add them up

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3 years ago

3x^2 - 4x = -2<br> Solve

amid [387]

Answer:

$x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

Step-by-step explanation:

$3 {x}^{2} - 4x = - 2 \\ 3 {x}^{2} - 4x + 2 = 0 \\ equating \: it \: with \\ a {x}^{2} + bx + c = 0 \\ a = 3 \: \: b = - 4 \: \: c = 2 \\ {b}^{2} - 4ac \\ = {( - 4)}^{2} - 4 \times 3 \times 2 \\ = 16 - 24 \\ = - 8 \\ \ {b}^{2} - 4ac < 0 \\ \therefore \: given \: quadratic \: equation \: have \: \\ imaginary \: solutios. \\ \\ x = \frac{ - b \pm \sqrt{{b}^{2} - 4ac } }{2a} \\ = \frac{ - ( - 4) \pm \sqrt{ - 8} }{2 \times 3} \\ = \frac{ 4 \pm 2\sqrt{2} \: i }{2 \times 3} \\ = \frac{ 2 \pm \sqrt{2} \: i }{3} \\ \therefore \: x = \frac{ 2 - \sqrt{2} \: i }{3} \: or \: x = \frac{ 2 + \sqrt{2} \: i }{3} \: \\ \\ x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

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3 years ago

What numbers should i put in the drop down menus? the numbers i can choose are 0-9.

ElenaW [278]

Answer:

1x+4 should be the answer

Step-by-step explanation:

6x-3x-2x=1x

4=4

6 0

3 years ago

A group of 8 people are picking up litter along a 4 over 5 km length of road. Each person is assigned an equal section of the ro

zepelin [54]

You know that 1 km=1000 m, then the length of the road $\dfrac{4}{5}$ km is $\dfrac{1000}{5} \cdot 4=200\cdot 4=800$ metres.

A group of 8 people are picking up litter along the road and each person is assigned an equal section of the road. The whole road has length 800 m, then for each person will be assigned 800:8=100 m of the road.

If you want to know the length of each part in km, then 1 m=0.001 km and 100 m =1 m·100=0.001 km ·100=0.1 km.

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2 years ago