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Rasek [7]
3 years ago
15

Solve the system Also plz show work and what you did and these two equations with x and y the x and y have to be the same in bot

h the equations 0.5x +y=4 0.5x-y=-1 what is the solution
Mathematics
1 answer:
Gala2k [10]3 years ago
5 0
Multply both equations by 2 leaving

x + 2y = 8
x - 2y = -2

Add the equations giving

2x = 6
x = 3

Substitute 3 in the top equation

3 + 2y = 8
2y = -5
y = -2.5
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Hi guys mind helping me with this
Anton [14]

Answer:

i actually have the same question  

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the x and y intercepts of y = 2x^3 - 4x^2 algebraically
poizon [28]

The x-intercept is the place where y = 0 and the y-intercept is the point where x = 0. Using this information, we can substitute 0 in for x and y to find the intercepts.


x-intercepts (where y = 0):

2x^3 - 4x^2 = 0

x^2(2x - 4) = 0

Here we can apply the Zero Product Property to find x^2 = 0 and 2x - 4 = 0 separately.

x^2 = 0

x = 0

AND

2x - 4 = 0

2x = 4

x = 2

The x-intercepts are located at (0, 0) and (2, 0).


y-intercept (where x = 0):

y = 2(0)^3 - 4(0)^2

y = 0

The y-intercept is located at (0, 0).

6 0
3 years ago
What is the area of the piece of red paper after the hole for
MakcuM [25]

Answer:

     \large\boxed{\large\boxed{47unit^2}}

Explanation:

The complete question is:

<em>A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.</em>

<em />

<em>On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).</em>

<em />

<em>What is the area of the piece of red paper after the hole for the photograph has been cut?</em>

<em />

<h2><em>Solution</em></h2>

<em />

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

<u>1. Area of the big rectangle</u>

Vertices:

  • <em>(- 4, 4) </em>
  • <em>(4, 4)</em>
  • <em>(4, -4)</em>
  • <em>(-4, -4)</em>

<em />

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

  • 4-(-4)=4+4=8

The area of this square is    (8unit)^2=64unit^2

<u>2. Area of the small square</u>

Vertices:

  • <em>(-3, -2)</em>
  • <em>(- 2, 2) </em>
  • <em>(2, 1)</em>
  • <em>(1, -3)</em>

<em />

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

      d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}

The area is:

          (\sqrt{17}unit)^2}=17unit^2

<u>3. Area of the piece of red paper after the holw for the photograph has been cut:</u>

<u />

Find the difference:

<u />

         64unit^2-17unit^2=47unit^2

<em />

7 0
3 years ago
Read 2 more answers
The standard form of the number represented by the Roman numeral MXCIV is
Assoli18 [71]

Answer:

1094

Step-by-step explanation:

4 0
2 years ago
On a graph with y-values ranging from 108,175 to 986,432, what is a reasonable scale to use on a y-axis with 10 tick marks?
Black_prince [1.1K]
Increments of 100,000. 
0 - 1,000,000
Essentially 0, 100,000, 200,000, 300,000, etc.
5 0
3 years ago
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