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gregori [183]
3 years ago
13

Consider the system of equations given in slope-intercept form. y = −13x + 17, y = 5x - 23 The solution seems to be about (8, 14

). Use the graphing calculator to find the exact values for the intersection point. What is the solution to this system of equations?
Mathematics
1 answer:
Nitella [24]3 years ago
4 0

Answer:

The exact solution for this equation would be (2.222, -11.889)

Step-by-step explanation:

Since it told us to use a graphing calculator, I went on to desmos graphing calculator, typed in the equation, then I found out where the two line intersect, and then that was the answer.

You might be interested in
Which is a greater y-intercept (0,-1) or (0,-2)
kolezko [41]

Answer:

(0,-1)

Step-by-step explanation:

-1 is less than -2 so -1 have a greater value since it is closer to the origin (0,0)

3 0
3 years ago
What is 66% of $444? (Round to the nearest whole number)
mezya [45]
$444-66%= $150.96= $151
8 0
3 years ago
Solve the equation below and find the variation constant, k .Find y when x = 7 and z=5, if y varies jointly as x and 2, and y= 1
Vlada [557]
<h3>Answers:</h3>

Variation Constant: k = 7/6

y = 245/6 when x = 7 and z = 5

====================================

Explanation:

"y varies jointly as x and z" means that y = kxz

We have (x,y,z) = (4,14,3) as one triple, so,

y = kxz

14 = k*4*3

14 = 12k

12k = 14

k = 14/12

k = 7/6 is the variation constant

The equation goes from y = kxz to y = (7/6)xz

----------------

Plug in x = 7 and z = 5 to find y

y = (7/6)xz

y = (7/6)*7*5

y = (7/6)*(7/1)*(5/1)

y = (7*7*5)/(6*1*1)

y = 245/6

4 0
3 years ago
The width of a rectangle is 3ft less than the length. The perimeter is 62ft. Find the length and width of the rectangle.
Assoli18 [71]
I believe the length of the rectangle is 17 ft and the width is 14
8 0
3 years ago
Binomial Probability
ASHA 777 [7]

Answer:

4.39% theoretical probability of this happening

Step-by-step explanation:

For each coin, there are only two possible outcomes. Either it lands on heads, or it lands on tails. The probability of a coin landing on heads is independent of other coins. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Theoretically, a fair coin

Equally as likely to land on heads or tails, so p = \frac{1}{2} = 0.5

10 coins:

This means that n = 10

What is the theoretical probability of this happening?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{10,2}.(0.5)^{2}.(0.5)^{8} = 0.0439

4.39% theoretical probability of this happening

6 0
3 years ago
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