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3 years ago

What does a2+b2=c2 mean ps yo you will get 20 points

1 answer:

6 0

That is for Geometry. So Pythagorean Theorem: a2 + b2 = c2. The Pythagorean Theorem is a formula that gives a relationship between the sides of a right triangle The Pythagorean Theorem only applies to RIGHT triangles. A RIGHT triangle is a triangle with a 90 degree angle.

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A car travels the 120 miles from A to B at 60 miles per hour, and then returns to A on the same road. If the average rate of the

inessss [21]

Outbound Trip 120 miles 60 mph equals 2 hours

Return Trip 120 miles

Total Trip 240 miles at 45 mph average speed

Total time = distance / rate = 240 / 45 = 5.3333333333 Hours

The return trip of 120 miles takes (5.3333333333 Hours MINUS 2 hours)

Return Trip Speed = 120 / 3.333333333 = 36 miles per hour

5 0

4 years ago

I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

NemiM [27]

Answer:

$- (x - 1) {}^{2} + 5$

Step-by-step explanation:

F(x) is a transformation from h(x).

So our starting equation is

$- (x - 1) {}^{2} - 1$

F(x) is also facing the same direction h(x) is so we dont have to reflect nothing across the x or y axis.

There isn't a vertical or horizontal stretch, compressions.

There isn't a horizontal shift as the x values stay in the same place.

There is a vertical shift. We can simply move h(x) up 6 units to get to f(x).

So our equation looks like.

$- (x - 1) {}^{2} + 5$

8 0

3 years ago

Why do you think city streets often are designed to be parallel or perpendicular?

White raven [17]

Answer:

Step-by-step explanation: Most urban designers incorporate a diagonal street cutting through the regular grid to create interesting spaces, squares, plazas, to provide relief and add character as can be seen at Manhattan Times Square created by Broadway cutting the grid at an angle.

7 0

3 years ago

Read 2 more answers

Financial advisors counsel young people to start saving early for their retirement. Explain why an early start is important.

Inessa05 [86]

Answer:

The more money you invest and the earlier you start means your retirement savings will have that much more time and potential to grow and investing early you can be able to take advantage of compound earnings.

Step-by-step explanation:

5 0

3 years ago

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

7 0

3 years ago