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3 years ago

Solve the following non-linear system. Show all work.

Mathematics

2 answers:

dybincka [34]3 years ago

8 0

Answer:

7y=x

Step-by-step explanation:

kolbaska11 [484]3 years ago

4 0

7y=x I hope it helps

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Jamal worked over summer at his dads office. He earned $2200 total. He is planning on spending his money on a $50 per month gym

Tju [1.3M]

Answer: He will have $1974 in April.

Step-by-step explanation:

Given : Total money he earned = $2200

He spent $50 per month gym membership, a $68 monthly phone plan $48 monthly gas plan and $60 monthly fun plan.

So , Money he has left = Money he earned - Total expenditure

= $ ( 2200- (50+68+48+60))

= $ (2200- 226)

= $ 1974

Hence, He will have $1974 in April.

3 0

2 years ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0

2 years ago

Megan's cousin wants to buy a new sound system for his car. She goes to the electronics store to help him to pick it out. The ba

Nikitich [7]

Answer:D

Step-by-step explanation:

5 0

3 years ago

The price of commodity a is 4500 and increases at the rate of $6 every three months. Commodity b costs $5400 and increases at ra

ivanzaharov [21]

Let x be the months and y be the cost.

Rate of increase of commodity A = 6/3 = $2 per month
Equation:
y = 2x + 4500

Rate of increase of commodity B = 2/4 = $0.5 per month
Equation:
y = 0.5x + 5400

Equating the costs,
2x + 4500 = 0.5x + 5400
1.5x = 900
x = 600 months
x = 600 / 12 = 50 years

5 0

3 years ago

Factor of 2x4+22x3+60x

horsena [70]

Remark

I don't know exactly what level you are in, but the obvious factors are

y = 2x*(x^3 + 11x + 30)

This gives one more factor somewhere around x = -11.3 . Notice that the minimum is around - 3000 or so. I don't think anyone is going to try and take this any further. My calculator figures out cubics and gives an answer of -11.23. There are two other roots but they are a complex pair.

Answer

factor 1: 2x

factor 2: x^3 + 11x^2 + 30

5 0

2 years ago