Question

Mr. Bray prepares a list of 43 US presidents, 8 of whom died in office. Then 18 of his students each select a

Answer 1

Answer:

The probability that at least one of the students select a president who died in office is 0.97541 or 97.541%

Step-by-step explanation:

Consider the provided information.

Mr. Bray prepares a list of 43 US presidents, 8 of whom died in office.

Therefore, $p=\frac{8}{43}$

If 8 out of 43 died in office then the number of president who didn't died in office is 43-8=35

$q=\frac{35}{43}$

Let X be the number of president who died in office.

The probability that at least one of the students select a president who died in office is:

$P(X\geq 1)=1-P(X=0)$

$P(X\geq 1)=1-^{18}C_0(\frac{8}{43})^0(\frac{35}{43})^{18}$

$P(X\geq 1)=1-(\frac{35}{43})^{18}$

$P(X\geq 1)=1-0.02459$

$P(X\geq 1)=0.97541$

Hence, the probability that at least one of the students select a president who died in office is 0.97541 or 97.541%

Answer 2

Answer:

.98

Step-by-step explanation:

1-(35/43)^18 im in stats too tehee