Question

The binomial (y − 2) is a factor of y2 − 10y + 16. What is the other factor?

Answer 1

Answer:

$\left(y-8\right)$

Step-by-step explanation:

$y^2-10y+16$

$=\left(y^2-2y\right)+\left(-8y+16\right)$

$y^2-2y$

$=yy-2y$

$=y\left(y-2\right)$

$-8y+16$

$=-8y+8\cdot \:2$

$=-8\left(y-2\right)$

$=y\left(y-2\right)-8\left(y-2\right)$

$=\left(y-2\right)\left(y-8\right)$

The other factor is:

$\left(y-8\right)$

Answer 2

Incase it helps to have a slightly different approach, the way we learnt it is:

y2 - 10y + 16 = 0

When these are factorised, the brackets you have will need to expand to equal the above.

You need to find 2 numbers that multiply together to make the end number, c, and those 2 numbers must also add together to made the middle number, b.

So for this case, those two numbers would be -2 and -8.

Then these go into the brackets,
(y - 2) (y - 8) = 0

This can then be proven to be correct via expansion,

y x y = y2
y x -8 = -8y
-2 x y = -2y
-2 x -8 = 16

(y2) + (-8y) + (-2y) + (16) = 0

y2 - 8y - 2y + 16 = 0

y2 - 10y + 16 = 0

Hope this helps a little?