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almond37 [142]
3 years ago
10

Find the cube of 2/3​

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0
In $ its $31.45 in number it’s 0.6666
Murrr4er [49]3 years ago
5 0

Answer:

8/27

Step-by-step explanation:

\huge \bigg( \frac{2}{3}  \bigg)^{3 }  =  \frac{ {2}^{3} }{ {3}^{3} }  =  \frac{8}{27}  \\

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Please help me, pic provide d
vfiekz [6]
Fill in the y of the bottom equation with the top equation because it gives you what Y equals. To answer the question it would be easier to input the top equation into the bottom one. Once you then get the equation for X go to the equation on top and fill in the x to get the y. X=0 Y=2
5 0
3 years ago
Which equation will solve the following word problem? News Center 13 has just released tomorrow's weather forecast. The high tem
WARRIOR [948]

Answer:

low temperature= high temperature/2 or X= 74/2

Step-by-step explanation:

The low is 37 btw

6 0
3 years ago
The vertices of a square are A(–2, 4), B(4, 4), C(4, –2), and D(–2, –2). The diagonals of the square intersect at their midpoint
sertanlavr [38]
A(–2, 4), B(4, 4), C(4, –2), D(–2, –2)
-> select some diagonal: AC
midpoint is at A+(1/2)*AC

-> calculate vector AC:
AC=(4-(-2),-2-4)=(6,-6)
-> calculate half length of AC:
(1/2)*AC=(3,-3)

A+(1/2)*AC=
(-2,4)+(3,-3)=(1,1) which is the midpoint

so the first option is correct
4 0
3 years ago
A prism has a volume 243 cubic meters. If it has a height of 3cm and its base is a square with the sides of (x+3)cm. Make an equ
aliya0001 [1]
243 = (x+3)^2 (3)

Hope this helps :)
5 0
3 years ago
Read 2 more answers
A new, simple test has been developed to detect a particular type of cancer. The test must be evaluated before it is used. A med
g100num [7]

Answer:

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test indicates cancer.

Event B: Person does not have cancer.

Probability of a test indicating cancer.

98% of 2%(those who have).

1% of 100 - 2 = 98%(those who do not have). So

P(A) = 0.98*0.02 + 0.01*0.98 = 0.0294

Probability of a test indicating cancer and person not having.

1% of 98%. So

P(A \cap B) = 0.01*0.98 = 0.0098

What is the probability of a randomly chosen person not having cancer given that the test indicates cancer?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0098}{0.0294} = 0.3333

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

3 0
3 years ago
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