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vitfil [10]
2 years ago
5

Venti cold brew coffee has approximately

Mathematics
1 answer:
Radda [10]2 years ago
8 0
The answer is:
144mg

Working out/ Explanation:
13% of 300mg = 39
39 times 4 = 156
300mg - 156mg = 144mg

Hope this helps!
Please give Brainliest!
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Isabella is playing a board game. The probability that Isabella will lose a turn on her next turn is 11%. Which word or phrase d
anzhelika [568]

Answer:

unlikely

Step-by-step explanation:

11% is closer to 0 than it is to 1/2. when something may occur, but significantly less than half of the time, we say it is unlikely

6 0
3 years ago
Someone please help me I’m so confused!!!
QveST [7]

Answer:

number one.  186in^{2}  number two.  36cm^{2}

Step-by-step explanation:

FOR NUMBER ONE:

the area of a trapezoid formula is   \frac{a+b}{2} h where a and b are the bases and h is the height. so we have to add in the numbers into the formula

\frac{12+15}{2} * 6\\ = <em>81</em>

and the paralellogram formula is b×h.  where b is the base and h is height

15 × 7 = <em>105</em>

so the area of the figure is 81 + 105 is 186 in^2

FOR NUMBER TWO:

the area of the square formula is s^{2}.   where s is the side

4^2 = <em>16</em>

and for the paralellogram is b × h

4 × 5 = <em>20</em>

so the area of the figure is 16 +20 = 36 in^2

hope this helps! ;)

5 0
3 years ago
Find the equation of a line with each of the following characteristics. a) parallel to the line y = 3x + 5 and has a y-intercept
Vedmedyk [2.9K]

Answer:

y = 1/2x - 1

Step-by-step explanation:

When you put all three equations from the question into a graph and then input the equation i just gave you it will be perpendicular to line B & C, also it will be parallel to line A. Finally you can check yourself that it also has a y-intercept of (0,-1) & an x-intercept of (2,0). Hopefully this helps out & gets brainliest. xD

4 0
3 years ago
Nicole has used 6 feet of ribbon.This represents 3/8 of the total amount of the ribbon she started with. How much ribbon did Nic
GalinKa [24]
3/8x=6. x=6*8/3. x=2*8. x=16. Nicole started with 16 feet of string.
5 0
3 years ago
Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan
Lunna [17]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 41  

    Alternate Hypothesis, H_A : \mu > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let \mu = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, H_0 : \mu \leq 41     {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean = 47

            σ = population standard deviation = 35

            n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em>  =  \frac{47-41}{\frac{35}{\sqrt{40} } }

                                      =  1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

                P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

                              = 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0
3 years ago
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