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2 years ago

Venti cold brew coffee has approximately

1 answer:

8 0

The answer is:
144mg

Working out/ Explanation:
13% of 300mg = 39
39 times 4 = 156
300mg - 156mg = 144mg

Hope this helps!
Please give Brainliest!

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Isabella is playing a board game. The probability that Isabella will lose a turn on her next turn is 11%. Which word or phrase d

anzhelika [568]

Answer:

unlikely

Step-by-step explanation:

11% is closer to 0 than it is to 1/2. when something may occur, but significantly less than half of the time, we say it is unlikely

6 0

3 years ago

Someone please help me I’m so confused!!!

QveST [7]

Answer:

number one. 186 $in^{2}$ number two. 36 $cm^{2}$

Step-by-step explanation:

FOR NUMBER ONE:

the area of a trapezoid formula is $\frac{a+b}{2} h$ where a and b are the bases and h is the height. so we have to add in the numbers into the formula

$\frac{12+15}{2} * 6\\$ = 81

and the paralellogram formula is b×h. where b is the base and h is height

15 × 7 = 105

so the area of the figure is 81 + 105 is 186 in^2

FOR NUMBER TWO:

the area of the square formula is $s^{2}$ . where s is the side

4^2 = 16

and for the paralellogram is b × h

4 × 5 = 20

so the area of the figure is 16 +20 = 36 in^2

hope this helps! ;)

5 0

3 years ago

Find the equation of a line with each of the following characteristics. a) parallel to the line y = 3x + 5 and has a y-intercept

Vedmedyk [2.9K]

Answer:

y = 1/2x - 1

Step-by-step explanation:

When you put all three equations from the question into a graph and then input the equation i just gave you it will be perpendicular to line B & C, also it will be parallel to line A. Finally you can check yourself that it also has a y-intercept of (0,-1) & an x-intercept of (2,0). Hopefully this helps out & gets brainliest. xD

4 0

3 years ago

Nicole has used 6 feet of ribbon.This represents 3/8 of the total amount of the ribbon she started with. How much ribbon did Nic

GalinKa [24]

3/8x=6. x=6*8/3. x=2*8. x=16. Nicole started with 16 feet of string.

5 0

3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago