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Reil [10]
3 years ago
5

Let f(x)=7^x and g(x)=7^x+2-4. Which transformations are needed to transform f(x) to the graph g(x)?

Mathematics
1 answer:
lidiya [134]3 years ago
6 0

Answer:

4. vertical translation 4 units down

6. horizontal translation 2 units to the right

Step-by-step explanation:

Given f(x)=7^x and g(x)=7^{x+2}-4

1. Adding 2 to x means horizontal translation 2 units to the right.

2. Subtracting 4 from the function 7^{x+2} means vertical translation 4 units down.

So, to transform the graph of the function f(x) to the graph of the function g(x), you need to translate the graph of the function f(x) horizontally 2 units to the right and vertically 4 units down.

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If 4/3divided by 1/6 then the value of p is between which of the following pairs of numbers
Lerok [7]

Answer:

7 and 9

Step-by-step explanation:

4/3÷1/6 = 4/3 × 6/1

= 8

So the value of p falls between the range of 7 and 9

3 0
3 years ago
1) x+30 = 40
soldier1979 [14.2K]

1)x+30=40

x=40-30

Answer :x=10

2)30-20+2x=10

10+2x=10

2x=0

Answer: x=0

3)3x-10+13=-2x+28

3x+3=-2x+28

3x+2x+3=28

3x+2x=28-3

5x=28-3

5x=25

x=5

4)13x-23-45=-7x+12

13x-68=-7x+12

13x+7x-68=12

13x+7x=12+68

20x=12+68

20x=80

x=4

5)2(x+4)=10x+24

2x+8=10x+24

2x-10x+8=24

2x-10x=24-8

-8x=24-8

-8x=16

x=-2

6)3(x-5)=1-(2x-4)

3x-15=1-(2x-4)

3x-15=1-2x+4

3x-15=5-2x

3x+2x-15=5

3x+2x=5+15

5x=5+15

5x=20

x=4

7)5x-10=15

5x=15+10

5x=25

x=5

8)x+4=x+6

4=6

no solution

PLEASE MARK ME AS BRAINLIEST

4 0
3 years ago
What is the complement of 57?
umka21 [38]
Complements are numbers that add 90. Since one is 57, the other has to add to 57. So 33 would add with 57 to get 90.
4 0
3 years ago
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
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3 years ago
Andrew can paint the​ neighbor's house 6 times as fast as Bailey. The year Andrew and Bailey worked​ together, it took them 7 da
maw [93]
Each will take 21 hours to paint it
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