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Reil [10]
3 years ago
5

Let f(x)=7^x and g(x)=7^x+2-4. Which transformations are needed to transform f(x) to the graph g(x)?

Mathematics
1 answer:
lidiya [134]3 years ago
6 0

Answer:

4. vertical translation 4 units down

6. horizontal translation 2 units to the right

Step-by-step explanation:

Given f(x)=7^x and g(x)=7^{x+2}-4

1. Adding 2 to x means horizontal translation 2 units to the right.

2. Subtracting 4 from the function 7^{x+2} means vertical translation 4 units down.

So, to transform the graph of the function f(x) to the graph of the function g(x), you need to translate the graph of the function f(x) horizontally 2 units to the right and vertically 4 units down.

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Round 10,386.145 to the nearest tenth
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Rounded to the nearest tenth would be one since the four isn't higher. So the answer would be 10,386.1. You did mean the tenths place right?? because could have also meant tenth(8)
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What is this expression in simplified form? 5v2 - 9v6 ​
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A n s w e r:

v^2(5-9v^4)

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2 years ago
16y5+4y5-12y3+15y3?<br> What is the simplified form?
Eddi Din [679]

Answer:

20y^5+3y^3

Step-by-step explanation:

16y^5 + 4y^5 -12y^3 + 15y^3

All we can do here is combine like terms (add those that have the same the same exponent)

20y^5+3y^3

Good luck!

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3 years ago
Read 2 more answers
Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh
a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let \overline{x} and \overline{y} be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume \overline{x} having with mean \mu_{1} and \overline{y} having mean \mu_{2}

Also we have given the variance is constant

A)

We can test hypothesis as

H0: \mu_{1} =  \mu_{2}H1: \mu_{1} > \mu_{2}

For this problem

Test statistic is

T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}

Where

s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

3 0
3 years ago
Find the range of the function y=-x^2-3x when the domain is {-5,0,2}
umka21 [38]

Answer: \{-10, 0 \}

Step-by-step explanation:

The range is the set of output values for the domain (the set of inputs).

  • When x=-5, y=-(-5)^{2}-3(-5)=-10.
  • When x=0, y=-0^{2}-3(0)=0.
  • When x=2, y=-2^{2}-3(2)=-10

So, the range is \boxed{\{-10, 0 \}}

4 0
2 years ago
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