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Naddika [18.5K]
2 years ago
6

Is 9 a solution to the equation 21=3p-5? Show work

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
4 0

Answer:

No

Step-by-step explanation:

21 = 3p - 5

<u>Step 1</u> : Add 5 on both sides

21 + 5 = 3p

26 = 3p

3p = 26

<u>Step 2</u> : Divide 3 on both sides

p = 26/3

Hence, the solution of the given equation is 26/3, not 9.

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If Mrs. Kliesch’s advanced class is 40% boys, and there are 12 boys, how many students are in her class?
den301095 [7]

Answer:

30 students

Step-by-step explanation:

40% boys and 12 boys so 60% is girls

40/100=12/x

x=30

30-12 is 18

so 30 students, 12 boys, and 18 girls.

3 0
3 years ago
Need help on this please and thank you
larisa [96]

Step-by-step explanation:

a. 4/7t =56

4t= 392

t=98

b. 4=1/2 b -12

4+12=1/2 b

16=1/2 b

so, b =32

4 0
3 years ago
Help! ASAP!!!
solniwko [45]

Answer:

7.2 units

Step-by-step explanation:

Coordinates of city A = (0, 0)

Coordinates of city B = (6, 4)

Use the distance formula to find the distance between the two cities as follows:

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(0, 0) = (x_1, y_1)

B(6, 4) = (x_2, y_2)

Plug in the values into the formula

AB = \sqrt{(6 - 0)^2 + (4 - 0)^2}

AB = \sqrt{(6)^2 + (4)^2}

AB = \sqrt{36 + 16} = \sqrt{52}

AB = 7.2 (nearest tenth)

6 0
4 years ago
Which answer represents a geometric sequence?
julia-pushkina [17]

Answer:

A.

Step-by-step explanation:

in A. your q is 3 so: a1=1 a2= a1*q=3 a3=a2*q=9 and so on.

i C. its almost the right answer too,but notice that a1 is 0. so 0*2 is still 0 so though it looks almost perfect the first number ruins it

7 0
3 years ago
Imagine you have a pair of six-sided dice. What's the
Ksivusya [100]

Answer:

The  probability of rolling a seven or rolling an even number  as the sum of the two dice is \frac{2}{3}    

Step-by-step explanation:

Given : Imagine you have a pair of six-sided dice.

To find : What's the  probability of rolling a seven or rolling an even number  as the sum of the two dice?

Solution :

Rolling a pair of six-sided dice,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Rolling a seven as the sum of the two dice are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)

Rolling an even number  as the sum of the two dice are (1,1),(1,3),(1, 5),(2, 2),(2, 4),(2, 6) ,(3, 1),(3, 3),(3, 5),(4, 2),(4, 4),(4, 6),(5, 1),(5, 3),(5, 5),(6, 2),(6, 4),(6, 6).

Favorable outcome of rolling a seven or rolling an even number  as the sum of the two dice are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1), (1,1),(1,3),(1, 5),(2, 2),(2, 4),(2, 6) ,(3, 1),(3, 3),(3, 5),(4, 2),(4, 4),(4, 6),(5, 1),(5, 3),(5, 5),(6, 2),(6, 4),(6, 6) - 24

The probability is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{24}{36}

\text{Probability}=\frac{2}{3}

Therefore, the  probability of rolling a seven or rolling an even number  as the sum of the two dice is \frac{2}{3}

5 0
3 years ago
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