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lakkis [162]
4 years ago
10

A company's logo was designed using circles of 3 different. sizes. The diameters of two of the circles are shown. Which measurem

ent is closest to the area of the largest circle in square centimeters?

Mathematics
1 answer:
Helga [31]4 years ago
4 0

Answer:

option D . 254.34cm^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

The options are:

A . 56.52cm^2

B . 141.30cm^2

C . 1,017.36cm^2

D . 254.34cm^2

step 1

Find the diameter of the largest circle

we know that

The diameter of the largest circle is equal to the sum of the diameter of the two inside circles

so

D=6+12=18\ cm

step 2

Find the area of the largest circle

we know that

The area of the circle is given by the formula

A=\pi r^2

we have

r=18/2=9\ cm ----> the radius is half the diameter

assume

\pi=3.14

substitute

A=(3.14)(9^2)=254.34\ cm^2

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The clearance between a pin and the collar around it is important for the proper performance of a disc drive for small computers
hichkok12 [17]

Answer:

(a) The distribution of (Y - X) is <em>N</em> (0.001, 0.0005).

(b) The probability that the pin will not fit inside the collar is 0.023.

Step-by-step explanation:

The random variable <em>X</em> is defined as the diameter of the pin and the random variable <em>Y</em> is defined as the diameter of the collar.

The distribution of <em>X</em> and <em>Y</em> is:

X\sim N(0.525, 0.0003)\\Y\sim N(0.526, 0.0004)

The random variables <em>X</em> and <em>Y</em> are independent of each other.

(a)

Compute the expected value of (Y - X) as follows:

E(Y-X)=E(Y)-E(X)=0.526-0.525=0.001

The mean of (Y - X) is 0.001.

Compute the variance of (Y - X) as follows:

V(Y-X)=V(Y)+V(X)-2Cov(X,Y)\\=V(Y)+V(X);\ X\ and\ Y\ are\ independent\\=0.0003^{2}+0.0004^{2}\\=0.00000025

SD(Y-X)=\sqrt{0.00000025}=0.0005

The standard deviation of (Y - X) is 0.0005.

Thus, the distribution of (Y - X) is <em>N</em> (0.001, 0.0005).

(b)

Compute the probability of [(Y - X) ≤ 0] as follows:

P(Y-X\leq 0)=P(\frac{(Y-X)-\mu_{Y-X}}{\sigma_{Y-X}}\leq \frac{0-0.001}{0.0005})=P(Z

*Use a <em>z</em>-table for the probability value.

Thus, the probability that the pin will not fit inside the collar is 0.023.

8 0
3 years ago
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