Question

What is the perimeter, in terms of x, of the triangle shown here?

Answer 1

Answer:

The perimeter of triangle is: $\mathbf{10x^2-x+18}$

Step-by-step explanation:

We need to find perimeter, in terms of x, of the triangle shown here.

The length of side 1: $(7x^2 - 12)$

The length of side 2: $(-5x + 30)$

The length of side 3: $(3x^2 + 4x)$

The formula used to find perimeter of triangle is: $Perimeter\: of\: triangle=Sum\:of\:length\:of\:all\:sides$

Putting values and finding perimeter:

$Perimeter\: of\: triangle=Sum\:of\:length\:of\:all\:sides\\Perimeter\: of\: triangle=(7x^2 - 12)+(-5x + 30)+(3x^2 + 4x)\\Perimeter\: of\: triangle= 7x^2-12-5x+30+3x^2+4x\\Perimeter\: of\: triangle=7x^2+3x^2-5x+4x-12+30\\Perimeter\: of\: triangle=10x^2-x+18$

So, The perimeter of triangle is: $\mathbf{10x^2-x+18}$