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irinina [24]
3 years ago
6

Find the perimeter of the figure. If you need to use Pi in your computation, approximate its value as 3.14. Rectangle topped by

a semicircle A rectangle topped by a semicircle. The rectangle has length of 18 meters and width of 15 meters. The circle has diameter 15 meters. a. 98.10 m b. 52.57 m c. 89.55 m d. 74.55 m Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer:

74.6 m

Step-by-step explanation:

First look at the rectangle, which is 15 meters wide horizontally and 18 meters long vertically.  This rectangle contributes 2(18 m) + 15 m to the perimeter (the 15 m side is the bottom of the figure).  That comes to 2(18) m + 15 m, or 51 m.

Next, look at the semicircle.  Its diameter is 15 m and thus its total circumference is approximately (3.14)(15 m), or 47.1 m.  We take only half of this circumference in calculating the perimeter of this figure:  23.6 m.

The total perimeter of this figure is 23.6 m + 51 m, or approximately 74.6 m.

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Answer:

-20 divided 5 is the right answer.

Your welcome!

Step-by-step explanation:

6 0
3 years ago
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What number goes on top
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I'm not sure what you're really talking about.

But I think you are talking about fractions.

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8 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ​ ,0)left parenthesis, plus min
lora16 [44]

Answer:

\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the  relation between the focus and semi major axes and semi minor axes as:

\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 }  \\ \\ \mathbf{c^2 = 49 } \\ \\  \mathbf{c = \sqrt{49 }}

The equation of ellipse formula is:

\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

and we know that \mathbf{a=\sqrt{49}  \ \  and  \  \ b=\sqrt{37}}

Thus ; the equation of the ellipse at the origin is

\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}

3 0
4 years ago
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LUCKY_DIMON [66]

Answer:

2/8

Step-by-step explanation:

1. take 1/8 and multiply it by 2/1

3 0
3 years ago
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What does B(0) = 0 mean
MissTica

Answer:

It means <u>what is the y-value of the given function, if 0 is substituted in for x.</u>

Hope this helps!

3 0
3 years ago
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