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disa [49]
3 years ago
12

Sara is serving wings and burgers at her party. Wings cost $6.00 per serving and burgers are $3.00 each. Sara knows that at leas

t 4 of her friends want wings. Sara must spend less than $45.00. Sara graphs a system of inequalities to determine how many servings of each kind of food she could serve to stay within her budget.
According to the dark blue area on the graph, which coordinate pair satisfies the system for the number of wing servings and burgers that Sara can serve?
A) (5, 4)
B) (2, 5)
C) (8, 3)
D) (6, 5)

Mathematics
2 answers:
vladimir1956 [14]3 years ago
4 0

Answer:

It’s A

Step-by-step explanation:

katrin2010 [14]3 years ago
3 0

Answer:

A) (5,4)

Step-by-step explanation:

Just take a look at the intersection in the dark blue area. The only point that fits in that area is A) (5,4). And this makes sense, but let's check it anyways:

5 wing + 4 burger < 45

5(6) + 4(3) < 45

42 < 45. If she bought one more burger, she would be at $45, and the problem asked us to be under $45, so this is our answer.

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denis-greek [22]

Answer:

what is the question ? Volume or surface area???

6 0
3 years ago
Simplify <br>it was x there so u not confused​
Mariulka [41]

Step-by-step explanation:

here's the solution: -

=》

\frac{x {}^{6} }{ {x}^{4} }  \times  {x}^{2}

=》

\frac{x \times x \times x \times x \times x \times x}{x  \times x \times x\times \: x }  \times x \times x

=》

x \times x \times x \times x

=》

{x}^{4}

5 0
3 years ago
Can't figure out where to put the parentheses
Shtirlitz [24]
8 times 4 and 8 divided by 2 i think
8 0
3 years ago
Read 2 more answers
The number of kilograms of water in a human body varies directly as the mass of the body. An 87​-kg person contains 58 kg of wat
katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form y=kx, where y varies directly with x and k is constant of variation.

We are told that an 87​-kg person contains 58 kg of water. We can represent this information in an equation as:

58=k\cdot 87

Let us find the constant of variation as:

\frac{58}{87}=\frac{k\cdot 87}{87}

\frac{29*2}{29*3}=k

\frac{2}{3}=k

The equation y=\frac{2}{3}x represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute x=75 in our given equation and solve for y.

y=\frac{2}{3}(75)

y=2(25)

y=50

Therefore, there are 50 kg of water in a 75​-kg person.

3 0
3 years ago
(x + 2) is raised to the fifth power. The third term of the expansion is:
WITCHER [35]
(x+2)^5
n = 3
r = 5
3rd term is 5x^3y^2
7 0
4 years ago
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