Step-by-step explanation:

- Length of MN ( Base ) = 8
- Length of NL ( Hypotenuse ) = 10

- Length of LM ( Perpendicular )


⤑ 
⤑ 
⤑ 
⤑ 
⤑ 

Hope I helped ! ツ
Have a wonderful day / night ! ♡
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Answer:
<h3>162.5 cm²</h3><h3>
Step-by-step explanation:</h3>
Area of a triangle = (BH)/2
Base= 25
Height=13
(25×13)/2= 162.5 cm²
Answer:
x = 6.6
Step-by-step explanation:
Data obtained from the question include the following:
Angle X = 15°
Angle Y° = 23°
Side y = 10
Side x =..?
The value of side x can be obtained by using the sine rule as shown below:
x/Sine X = y/Sine Y
x/Sine 15 = 10/Sine 23
Cross multiply
x × Sine 23 = 10 × Sine 15
Divide both side by Sine 23
x = (10 × Sine 15) / Sine 23
x = 6.6
Therefore, the value of x is 6.6.
Answer:
<em>(a) x=2, y=-1</em>
<em>(b) x=2, y=2</em>
<em>(c)</em> 
<em>(d) x=-2, y=-7</em>
Step-by-step explanation:
<u>Cramer's Rule</u>
It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.
It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

We call the determinant of the system

We also define:

And

The solution for x and y is


(a) The system to solve is

Calculating:





The solution is x=2, y=-1
(b) The system to solve is

Calculating:





The solution is x=2, y=2
(c) The system to solve is

Calculating:





The solution is

(d) The system to solve is

Calculating:





The solution is x=-2, y=-7
75/100 x/56
Then do the math to find what's <span>75% of 56.</span>