All categories

3 years ago

8(2x-3)-6x if 3=x and simplify

1 answer:

5 0

Simplify the expression:

8(2x - 3) - 6x = 8×2x - 8×3 - 6x = 16x - 24 - 6x = 10x - 24

for x=3

put value of "x" to the expression:

<u>10×3 - 24 = 30 - 24 = 6</u>

You might be interested in

The scatter plot below shows the high temperature for one day and the number of coats in the theater coat check on that same day

Setler [38]

Answer:

the number of coats in the coat check will most likely decrease if the temperatures decrease.

Step-by-step explanation:

Im guessing this answer: Number of coats in the coat check will decrease because the graph shows negative association

But it could also be this answer: Number of coats in the coat check will decrease because the graph shows positive association

I think the graph shows a negative association because when the temperature goes down, the coat check goes down as well

6 0

2 years ago

Read 2 more answers

Please help me with this problem

igor_vitrenko [27]

Draw a circle 5 CM find the length then divid that

7 0

3 years ago

Write an equation of a line that passes through (-12, -14) with slope 6.

damaskus [11]

The slope intercept form of a line is y = mx + b

m = slope
b = y-intercept

Plug in the slope, 6, into m.

Rewrite the equation;

y = 6x + b
We need to find b, your y-intercept, to finish this equation.

Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.

-14 = 6(-12) + b

Solve for b to find the y-intercept.

-14 = -72 + b
58 = b

Your new equation (your answer) is<em> </em>y = 6x + 58.

6 0

3 years ago

Find the measure of angle AEC

andreev551 [17]

Aec= 40

Explanation because it’s a 90 degree angle and dea = 50
So 90-50=40
Plea give me Brainiest

7 0

3 years ago

Read 2 more answers

Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u

Tamiku [17]

Answer:

Step-by-step explanation:

15. $\frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx} \\$

16. $\frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }$

$=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2} \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\$

=> The clause is correct

17. Do the same (16)

18. $\frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx$

19.

$\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\$

=> The clause is correct

20. Do the same (18)

21. Left = $\frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA} } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}$

Right = $cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA} \\$

Same with (16) => Left = Right => The clause is correct

22. Do the same (21)

Too long, i'm so lazy :))))

5 0

3 years ago