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3 years ago

Solve using substitution -3x-4y=-2 y=2x-5

Mathematics

2 answers:

slavikrds [6]3 years ago

8 0

1) I )-3X-4Y = -2

Y = 2X-5, substitute it in I

-3X-4(2X-5) = -2 ⇒-3X-8X+20 = -2⇒-11X = -2-20 ⇒(-1) -11X = -22 ⇒11X= 22⇒X= 22/11 ⇒X= 2

Alik [6]3 years ago

4 0

-2/3,19/3. X=-2/3. Y=-19/3

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3 years ago

Beth’s music playlist contains songs she bought and songs her mother bought. The ratio of her songs to her mother’s songs is 3:2

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Step-by-step explanation:

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4 years ago

If x = 5 cm, y = 12 cm, and z = 13 cm, what is the surface area of the geometric shape formed by this net?

Lera25 [3.4K]

Answer:

the answer is C. 210 sq. cm

Step-by-step explanation:

Find the area of the triangle

The area of one of the triangular faces can be found by using the formula below.

a = 1/2 bh

a = 1/2 (5 cm) (12 cm)

a = 30 sq. cm

Since there are two triangular faces, multiply the area of one triangular face by 2. The area of two triangular faces is 60 cm2.

Next, find the area of each of the three rectangular faces using the formula, area = lw.

1st rectangle

a = lw

a = (5 cm) (5 cm)

a = 25 sq. cm

2nd rectangle

a = lw

a = (5 cm) (12 cm)

a = 60 sq. cm

3rd rectangle

a = lw

a = (5 cm) (13 cm)

a - 65 sq. cm

Add the three rectangle areas to find a total of 150 sq. cm.

To find the surface area of the triangular prism, add the area of the two triangular faces to the area of the three rectangular faces.

60 sq. cm + 150 sq. cm = 210 sq. cm

4 0

3 years ago

Choose all options that apply. Which of the following are equal to 20%? | a) .25 b) 1/5 Oc) 1/10 d) .20

zloy xaker [14]

Answer:

b. and d.

Step-by-step explanation:

$20 = \frac{20}{100} \\ 0.25 = \frac{25}{100} \\ \frac{1}{5} = \frac{20}{100} \\ \frac{1}{10} = \frac{10}{100} \\ 0.20 = \frac{20}{100}$

4 0

3 years ago

A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th

Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

$\tan\theta=\frac{Perpendicular}{base}$

Here, $\theta=11.1^{\circ}$ ,Perpendicular AB = 4000

$\tan\theta=\frac{AB}{BC}$

$\tan 11.1^{\circ} =\frac{4000}{BC}$

Solving for BC, we get,

$BC=\frac{4000}{\tan 11.1^{\circ} }$

$BC=\frac{4000}{0.196}$ (approx)

$BC=20408.16$ (approx)

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0

3 years ago