The set of values of x for which y will be a real number according to Y=8/x-3 includes all real numbers except x = 3.
<em>Real numbers in mathematics include the positive and negative integers and fractions (or rational numbers) and also the irrational numbers.</em>
- In essence, the expression Y=8/x-3 only ceases to yield a real number value for y if the denominator becomes zero.
When the denominator becomes zero, the value of y becomes undefined and thus is not a real number.
Therefore, if we set;
Consequently, the set of values of x for which y will be a real number according to Y=8/x-3 includes all real numbers except x = 3.
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<em>Answer:</em>
<em>Ello mate, Here are all your answers !</em>
<em>Step-By-Step-Explanation:</em>
<em>Answer 1 :</em><em> 
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<em>Answer 2 : </em><em>
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<em>Answer 3 : </em><em>
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I do believe it’s the first and third option that are correct as for standard form you go from left to right starting with the highest exponent to the lowest and constantes will always be on the right side
Answer: x>-6
Explanation: -2x -6>-18
-2x >-12
-x>6
X>-6
Answer:
y-12=4y = -4 (please like my answer)
Step-by-step explanation:
6n-12=3(2n-4)
6n-12=6n-12= 0
