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3 years ago

More easy math for points

Mathematics

2 answers:

user100 [1]3 years ago

5 0

256*16 is the correct answer here.

Nataliya [291]3 years ago

5 0

Answer:

4096

Step-by-step explanation:

Math

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The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.4 V and b = -5.10 V/m.

Minchanka [31]

Answer:

$V(0)=15.4\\V(3)=0.1\\V(6)=-15.2$

Step-by-step explanation:

The potential in a region between x = 0 and x = 6.00 m is V = a + bx.

Put a = 15.4 V and b = -5.10 V/m.

So, $V=15.4-5.10x$

To find: Potential at x =0, 3, 6

Solution:

Potential at x = 0:

$V=15.4-0=15.4$

Potential at x = 3:

$V=15.4-5.10(3)=15.4-15.3=0.1$

Potential at x = 6:

$V=15.4-5.10(6)=15.4-30.60=-15.2$

Therefore,

$V(0)=15.4\\V(3)=0.1\\V(6)=-15.2$

7 0

4 years ago

Convert to rectangular form r=4 cos theta

Amiraneli [1.4K]

Hello,

x=r cos t
y=r sin t
x²+y²=r²

r=4 cos t
r=4x/r==>x²+y²=4x
==>(x-2)²+y²=4 (a circle center (2,0),radius 2)

5 0

4 years ago

Read 2 more answers

In a two-digit number, the units digit is 5 more that the tenth digit. The number itself is three times the sum of its digits. W

postnew [5]

Answer:

Step-by-step explanation:

1+5=6

6*3=15

7 0

3 years ago

Read 2 more answers

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago

Draw the following scenario using a vertical number line.

nekit [7.7K]

You would move your point 24 up from the starting point then move it three down from the 24 so if you start at zero go to 24 then move it down to 21.

3 0

3 years ago