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2 years ago

Which equation represents a line that passes through (2, -1) and has a slope of 3?

Mathematics

1 answer:

777dan777 [17]2 years ago

5 0

Answer:

y+1=3(x-2)

Step-by-step explanation:

The explanation is in the picture

Please mark as brainliest

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Which State is directly east of North Dakota

kari74 [83]

The state that is directly north to north docoda is Minnesota

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3 years ago

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Milton needs to find the product of two numbers. one of the numbers is 9. The answer also needs to be 9. how will he solve this

galben [10]

The answer to this problem is one because nine times one equals nine which the answer is still nine

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3 years ago

Please help me with this i need help she is gonna call my mom again!!!

telo118 [61]

Answer:

1. 15

2. -23

3. -16

Step-by-step explanation:

1. Find h(-8)

h(t) = $\frac{5}{4}(4 - t)$

h(-8) = $\frac{5}{4}(4 -(-8))$

h(-8) = $\frac{5}{4}(4+8) =\frac{5}{4}(12)=5(3)=15$

2. What is the value of g(-3)

g(x) = 4(x - 5) + $x^{2}$

g(-3) = 4(-3 - 5) $-3^{2}$

g(-3) = 4(-8) + 9

g(-3) = -32 + 9

g(-3) = -23

3. Find f(10)

f(x) = 14 - 3x

f(10) = 14 - 3(10)

f(10) = 14 - 30

f(10) = -16

7 0

2 years ago

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Pls help thx luv y’a

garik1379 [7]

Answer:

8.39958×10(raised to power of eight)

3 0

3 years ago

Use mathematical induction to prove

Alex17521 [72]

$Prove\ that\ the\ assumption \is \true for\ n=1\\1^3=\frac{1^2(1+1)^2}{4}\\ 1=\frac{4}{4}=1\\$

Formula works when n=1

Assume the formula also works, when n=k.

Prove that the formula works, when n=k+1

$1^3+2^3+3^3...+k^3+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k+1)^2}{4}+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k^2+2k+1)}{4}+(k+1)^3=\frac{(k^2+2k+1)(k^2+4k+4)}{4} \\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+4k^3+4k^2+2k^3+8k^2+8k+k^2+4k+4}{4}\\\\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+2k^3+k^2}{4}+\frac{4k^3+12k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+6k^3+13k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\$

Since the formula has been proven with n=1 and n=k+1, it is true. $\square$

7 0

2 years ago