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ZanzabumX [31]
3 years ago
13

11.) The area of a garden is 152 square feet. If the length is 7 feet, what is the

Mathematics
2 answers:
Masja [62]3 years ago
8 0

Answer:

about 22 feet (21.7)

Step-by-step explanation:

Divide 152 by 7 and you get the width

DerKrebs [107]3 years ago
8 0

Multiply

Step-by-step explanation: multiply the two numbers and that's your answer

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2(x+19)=3(y-14) is equivalent to (2,6).<br><br> a.true<br> b.false
4vir4ik [10]

Answer:

false..........................

8 0
3 years ago
Suppose that the functions h and g are defined as follows.
never [62]
(h/g)(-4)
\frac{(-4)-5}{(-4+2)(-4+3)}
Plug and chug
Should come out to be -4.5
\frac{x-5}{(x+2)(x+3)}
To find the values not in the domain, you must set each quantity in the denominator equal to zero and solve for x.
x+2=0   x+3=0
x≠-2      x≠-3
If x were either of these numbers, the denominator of the fraction would equal zero, which would give an undefined answer.
3 0
4 years ago
Complete the following table relating the diameter and circumference of different circles. Round values to the nearest hundredth
Sedaia [141]

Answer:

9.42

8.60

4.71

4.39

Step-by-step explanation:

The equation to finding the circumference is πd=C

So for the row with the diameter of 3, you would multiply 3x3.14 to get 9.42

For the next row, you would set up 27=(3.14)d and you would divide the 27 by 3.14 to get 8.60

Next row, multiply 1.5 by 3.14 to get 4.71

Last row, set up the equation 13.8=(3.14)d and divide by 13.8 by 3.14 to get 4.39

3 0
3 years ago
Find the sum of the geometric series.<br> 8+6+9/2+27/8+...
Tema [17]

Answer: The answer is 58. Hope this helps!

3 0
3 years ago
Read 2 more answers
Rewrite each expression so that each term is in the form kxn, where k is a real number, x is a positive real number,
MaRussiya [10]

Answer:

So the equation in standard form will be x^{\frac{-1}{3}}  

Step-by-step explanation:

We have given equation x^{\frac{-2}{3}}\times x^{\frac{1}{3}}

We have to write this expression in standard form

For writing in standard form first we have to do operation on the expression

We know that there is property of exponent that when two functions are multiplied with each other then there exponent are added

So x^{\frac{-2}{3}}\times x^{\frac{1}{3}}=x^{\frac{-2}{3}+\frac{1}{3}}=x^{\frac{-1}{3}}

So the equation in standard form will be x^{\frac{-1}{3}}

6 0
3 years ago
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