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g100num [7]
2 years ago
12

Approximate: log5 4/7

Mathematics
2 answers:
sergiy2304 [10]2 years ago
7 0

for the first question which would be Approximate: log5 4/7 the answer would be B. –0.3477

and for the second question which would be Approximate: log1/2 5 the answer would be C.–2.3219

 


Evgesh-ka [11]2 years ago
6 0
   Properties of Logs

logb(x/y) = log<span>bx</span> - log<span>by</span>.

therefore

log5 (4/7)= log5 (4)- log5 (7)

<span>Solve log 5 (4) and log 5 (7)  with the base change of the logarithm</span>

<span>log 5 4 = log 4 / log 5 </span>

 Use the calculator: 

<span> <span>log 5 4 =0.8613531161 </span></span>

 log 5 7 = log 7 / log 5 

<span>log 5 7 =1.2090619551</span>

<span>log5 (4/7)= log5 (4)- log5 (7)=-0.347708839</span>

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3 years ago
3. Find the product of 25x^2y and -6x²y3
mojhsa [17]

Answer:

-150 (x^2y+2)y³

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3 years ago
X²+25<br>factor and find gcf first​
ozzi

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the answer of the GCF is 1

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2 years ago
Elimination using addition and subtraction. <br> -4x+4y=-20<br> -2x+4y=-2
goldfiish [28.3K]

I would subtract the 2nd from the first one

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now I would divide that by -2 to get the value for x

so no we have x = 9


now you just have to substitute that into one of the equations and simplify to get y


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3 0
3 years ago
Read 2 more answers
How do you solve 9 - x = 10 using algebraic operations?
vfiekz [6]
9 - x = 10\\&#10;-x=1\\&#10;x=-1
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