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dimaraw [331]
2 years ago
8

Find the product. (x2 + 3х - 2)(х + 3)​

Mathematics
1 answer:
g100num [7]2 years ago
8 0

<u>x-3</u>

x+7

its suppose to be at fraction

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The endpoints of RS are R: (9,-4) and S: (2, -8).
Vladimir79 [104]

Answer:

B, (11/2,-6)

Step-by-step explanation:

to get the midpoint of two endpoints, simply take the average of each corresponding coordinate

midpoint: ((Rx+Sx)/2,(Ry+Sy/2)).

((9+2/2),(-4+-8/2)) = (11/2,-12/2) = (11/2,-6)

the midpoint formula in general is : ((x+x1)/2),(y+y1)/2))

where x1 is the initial or first x coordinate, y1 is the initial or first y coordinate, x is the second, last, or final x coordinate. and y is the second, last, or final y coordinate.

7 0
2 years ago
A triangle has an angle that measures 10°. The other two angles are in a ratio of 7:10. What are the measures of those two angle
Sliva [168]

Answer:

100 degrees and 70 degrees

Step-by-step explanation:

180 - 10 = 170

with a ratio of 7:10

7x + 10x = 170

17x = 170

x = 170/17    

x = 10

one angle in 100 degrees and the other is 70 degrees

4 0
2 years ago
What is this questions anwser?? <br>928=1820+x
grandymaker [24]
928 = 1820 + x

Subtract 1820 from both sides.

928 - 1820 = x

Simplify.

x = -892

~Hope I helped!~
6 0
3 years ago
Read 2 more answers
Yuri computes the mean and standard deviation for the sample data set 12, 14, 9, and 21. He finds the mean is 14. His steps for
Tpy6a [65]

Answer:

B. Yuri divided by n instead of n-1

Step-by-step explanation:

It was stated in the question that the dataset was sample dataset. For a sample dataset, the standard deviation is given by the formula,

σ = √ Σ (Xi - mean)²/(n - 1) where i = 1,2,3.....n

Since this is just a sample dataset and not the whole population, Yuri should have divided by n-1 instead of n.

3 0
3 years ago
A data set includes 108 body temperatures of healthy adult humans having a mean of 98.3degrees°F and a standard deviation of 0.6
mylen [45]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n=106

Sample mean : \overline{x}=98.3^{\circ}\ F

Standard deviation : \sigma= 0.69^{\circ}F

Significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Then , 99​% confidence interval estimate of the mean body temperature of all healthy humans will be :-

98.3\pm (2.576)\dfrac{0.69}{\sqrt{106}}\\\\\approx98.3\pm0.173=(98.3-0.173,\ 98.3+0.173)=(98.127,\ 98.473)

Since 98.6 is higher than the upper limit of the confidence interval (98.473), then this suggest that the mean body temperature could be lower then 98.6 degrees.

The best estimate of population mean is always the sample mean. \mu=\overline{x}=98.3^{\circ}\ F

7 0
3 years ago
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